Digital Signal Processing Reference
In-Depth Information
Tutorial 11
Q: For the periodic pulse train p
ð
t
Þ¼
P
k
¼1
d
ð
t
kT
Þ
find:
(A) Complex Fourier series (FS), (B) trigonometric FS, (C) Fourier Transform
(FT).
p
(
t
)
1
t
−4
T
o
−3
T
o
−2
T
o
−
T
o
T
o
2
T
o
3
T
o
4
T
o
0
Solution:
(A) p
ð
t
Þ¼
P
1
k
¼1
P
k
e
þ
j2pkf
o
t
;
where x
o
¼
2pf
o
¼
2
T
o
is the fundamental
frequency, T
o
being the fundamental period, and the Fourier coefficients are
given by [see Tables]:
Z
T
o
=
2
T
o
=
2
Z
P
o
¼
1
T
o
p
ð
t
Þ
dt
¼
1
T
o
d
ð
t
Þ
dt
¼
1
T
o
T
o
=
2
T
o
=
2
T
o
=
2
T
o
=
2
Z
Z
P
k
¼
1
T
o
p
ð
t
Þ
e
j2pkf
0
t
dt
¼
1
T
o
d
ð
t
Þ
e
j2pkf
0
t
dt
¼
1
T
o
T
o
=
2
T
o
=
2
X
1
p
ð
t
Þ¼
1
T
o
e
j2pkf
0
t
)
1
(B) p
ð
t
Þ¼
a
o
þ
P
1
k
¼
1
½
a
k
cos
ð
kx
o
t
Þþ
b
k
sin
ð
kx
o
t
Þ
, where [see Tables]:
a
o
¼
P
o
¼
1
a
k
¼
P
k
þ
P
k
¼
2
T
o
;
T
o
;
b
k
¼
j
ð
P
k
P
k
Þ¼
0
:
X
1
p
ð
t
Þ¼
1
T
o
þ
2
T
o
)
cos
ð
kx
o
t
Þ:
k
¼
1
(C) Using part (A) we have [using Tables]:
(
)
X
X
1
1
Ff
p
ð
t
Þg¼F
1
T
o
¼
1
T
o
e
j2pkf
o
t
F
e
j2pkf
o
t
k
¼1
k
¼1
X
d
ð
f
kf
o
Þ¼
f
o
X
1
1
¼
1
T
o
d
ð
f
kf
o
Þ
k
1
k
1
Hence, a pulse train in the time domain is Fourier-transformed to a pulse train in
the frequency domain.
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