Digital Signal Processing Reference
In-Depth Information
Tutorial 11
Q: For the periodic pulse train p ð t Þ¼ P k ¼1 d ð t kT Þ find:
(A) Complex Fourier series (FS), (B) trigonometric FS, (C) Fourier Transform
(FT).
p ( t )
1
t
−4 T o
−3 T o
−2 T o
T o
T o
2 T o
3 T o
4 T o
0
Solution:
(A) p ð t Þ¼ P 1
k ¼1 P k e þ j2pkf o t ; where x o ¼ 2pf o ¼ 2 T o is the fundamental
frequency, T o being the fundamental period, and the Fourier coefficients are
given by [see Tables]:
Z
T o = 2
T o = 2
Z
P o ¼ 1
T o
p ð t Þ dt ¼ 1
T o
d ð t Þ dt ¼ 1
T o
T o = 2
T o = 2
T o = 2
T o = 2
Z
Z
P k ¼ 1
T o
p ð t Þ e j2pkf 0 t dt ¼ 1
T o
d ð t Þ e j2pkf 0 t dt ¼ 1
T o
T o = 2
T o = 2
X
1
p ð t Þ¼ 1
T o
e j2pkf 0 t
)
1
(B) p ð t Þ¼ a o þ P 1
k ¼ 1 ½ a k cos ð kx o t Þþ b k sin ð kx o t Þ , where [see Tables]:
a o ¼ P o ¼ 1
a k ¼ P k þ P k ¼ 2
T o ;
T o ;
b k ¼ j ð P k P k Þ¼ 0 :
X
1
p ð t Þ¼ 1
T o
þ 2
T o
)
cos ð kx o t Þ:
k ¼ 1
(C) Using part (A) we have [using Tables]:
(
)
X
X
1
1
Ff p ð t Þg¼F 1
T o
¼ 1
T o
e j2pkf o t
F e j2pkf o t
k ¼1
k ¼1
X
d ð f kf o Þ¼ f o X
1
1
¼ 1
T o
d ð f kf o Þ
k 1
k 1
Hence, a pulse train in the time domain is Fourier-transformed to a pulse train in
the frequency domain.
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