Digital Signal Processing Reference
In-Depth Information
Now: / ð t o Þ¼ g ð t o Þ x ð t o Þ¼ x ð t Þ R 1
1 g ð t Þ d ð t t o Þ dt ¼ R 1
1 g ð t Þ½ x ð t o Þ d ð t t o Þ dt :
Hence we have: R 1
dt ¼ R 1
1 g ð t Þ½ x ð t Þ d ð t t o Þ
1 g ð t Þ½ x ð t o Þ d ð t t o Þ
dt
|{z}
s ð t Þ
|{z}
r ð t Þ
Since g(t) is arbitrary, the above equation implies that:
s ð t Þ¼ r ð t Þ;
or
x ð t Þ d ð t t o Þ¼ x ð t o Þ d ð t t o Þ:
Q2: Consider the cascaded and parallel systems shown in Figs. a and b . Find the
equivalent impulse responses for the equivalent system shown in Fig. c .
(c)
(a)
(b)
h 1 ( t )
x ( t )
y ( t )
x ( t )
h ( t )
y ( t )
h 1 ( t )
h 2 ( t )
x ( t )
y ( t )
h 2 ( t )
Solution:
(a) Let y 1 (t) = x(t)*h 1 (t).
)
y ð t Þ¼ y 1 ð t Þ h 2 ð t Þ¼½ x ð t Þ h 1 ð t Þ h 2 ð t Þ¼ x ð t Þ½ h 1 ð t Þ h 2 ð t Þ
|{z}
h ð t Þ
) h ð t Þ
¼ h 1 ð t Þ h 2 ð t Þ
where we used the associative property of convolution.
(b) Let y 1 (t) = x(t)*h 1 (t), y 2 (t) = x(t)*h 2 (t).
)
y ð t Þ¼ y 1 ð t Þþ y 2 ð t Þ¼ x ð t Þ h 1 ð t Þþ x ð t Þ h 2 ð t Þ¼ x ð t Þ½ h 1 ð t Þþ h 2 ð t Þ
|{z}
h ð t Þ
) h ð t Þ
¼ h 1 ð t Þþ h 2 ð t Þ
where we used the distributive property of convolution.
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