Digital Signal Processing Reference
In-Depth Information
Now: /
ð
t
o
Þ¼
g
ð
t
o
Þ
x
ð
t
o
Þ¼
x
ð
t
Þ
R
1
1
g
ð
t
Þ
d
ð
t
t
o
Þ
dt
¼
R
1
1
g
ð
t
Þ½
x
ð
t
o
Þ
d
ð
t
t
o
Þ
dt
:
Hence we have:
R
1
dt
¼
R
1
1
g
ð
t
Þ½
x
ð
t
Þ
d
ð
t
t
o
Þ
1
g
ð
t
Þ½
x
ð
t
o
Þ
d
ð
t
t
o
Þ
dt
|{z}
s
ð
t
Þ
|{z}
r
ð
t
Þ
Since g(t) is arbitrary, the above equation implies that:
s
ð
t
Þ¼
r
ð
t
Þ;
or
x
ð
t
Þ
d
ð
t
t
o
Þ¼
x
ð
t
o
Þ
d
ð
t
t
o
Þ:
Q2: Consider the cascaded and parallel systems shown in Figs.
a
and
b
. Find the
equivalent impulse responses for the equivalent system shown in Fig.
c
.
(c)
(a)
(b)
h
1
(
t
)
x
(
t
)
y
(
t
)
x
(
t
)
h
(
t
)
y
(
t
)
h
1
(
t
)
h
2
(
t
)
x
(
t
)
y
(
t
)
h
2
(
t
)
Solution:
(a) Let y
1
(t) = x(t)*h
1
(t).
)
y
ð
t
Þ¼
y
1
ð
t
Þ
h
2
ð
t
Þ¼½
x
ð
t
Þ
h
1
ð
t
Þ
h
2
ð
t
Þ¼
x
ð
t
Þ½
h
1
ð
t
Þ
h
2
ð
t
Þ
|{z}
h
ð
t
Þ
)
h
ð
t
Þ
¼
h
1
ð
t
Þ
h
2
ð
t
Þ
where we used the associative property of convolution.
(b) Let y
1
(t) = x(t)*h
1
(t), y
2
(t) = x(t)*h
2
(t).
)
y
ð
t
Þ¼
y
1
ð
t
Þþ
y
2
ð
t
Þ¼
x
ð
t
Þ
h
1
ð
t
Þþ
x
ð
t
Þ
h
2
ð
t
Þ¼
x
ð
t
Þ½
h
1
ð
t
Þþ
h
2
ð
t
Þ
|{z}
h
ð
t
Þ
)
h
ð
t
Þ
¼
h
1
ð
t
Þþ
h
2
ð
t
Þ
where we used the distributive property of convolution.
Search WWH ::
Custom Search