Information Technology Reference
In-Depth Information
>
Theorem 1.34 (Xia et al. 2012c) If r
0, then
ATS
IFWA
(
r
α 1 ,
r
α 2 ,...,
r
α n ) =
rATS
IFWA
1 2 ,...,α n )
(1.220)
Proof According to Definition 1.21, we have
h 1
α i )), g 1
r
α =
(
rh
(
r g(
v
))
(1.221)
α
i
then
ATS
IFWA
(
r
α 1 ,
r
α 2 ,...,
r
α n )
h 1 k + 1
, g 1 k + 1
h 1
w i g(g 1
=
w i h
(
(
rh
α i )))
(
r g(
v
α i )))
i
=
1
i
=
1
h 1 k + 1
, g 1 k + 1
=
w i (
rh
α i ))
w i (
r g(
v α i ))
(1.222)
i
=
1
i
=
1
and
rATS
IFWA
1 2 ,...,α n )
h 1 rh h 1 n
, g 1 r g
g 1 n
=
w i h
α i )
w i g(
v α i )
i
=
1
i
=
1
h 1 r
, g 1 r
n
n
=
w i h
α i )
w i g(
v
)
(1.223)
α i
i
=
1
i
=
1
According to Theorems 1.33 and 1.34, we can get the following result easily:
Theorem 1.35 (Xia et al. 2012c) If r
>
0, and
β = β ,
v
β )
is an IFV, then
ATS
IFWA
(
r
α 1 β,
r
α 2 β,...,
r
α n β) =
rATS
IFWA
1 2 ,...,α n ) β
(1.224)
Theorem 1.36 (Xia et al. 2012c) Let
β i
= β i ,
v β i )(
i
=
1
,
2
,...,
n
)
be a
T
collection of IFVs, and w
= (
w 1 ,
w 2 ,...,
w n )
their weight vector, such that
i = 1 w i
=
1, then
ATS
IFWA
1 β 1 2 β 2 ,...,α n β n )
=
ATS
IFWA
1 2 ,...,α n )
ATS
IFWA
1 2 ,...,β n )
(1.225)
Proof According to Definition 1.21, we have
h 1
β i )), g 1
α i β i
=
(
h
α i ) +
h
(g(
v
) + g(
v
))
(1.226)
α
β
i
i
Search WWH ::




Custom Search