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Based on Theorem 1.31, the following property can be obtained:
α
−
α
+
be given by Eqs. (
1.179
) and
Theorem 1.32
(Xia et al. 2012c) Let
and
(
1.180
), then
α
−
≤
(α
1
,α
2
,...,α
n
)
≤
α
+
ATS
−
IFWA
(1.215)
T
be the weight vector
Theorem 1.33
(Xia et al. 2012c) Let
w
=
(
w
1
,
w
2
,...,
w
n
)
, such that
i
=
1
w
i
of the IFVs
α
i
(
i
=
1
,
2
,...,
n
)
=
1. If
β
=
(μ
β
,
v
β
)
is an IFV,
then
ATS
−
IFWA
(α
1
⊕
β, α
2
⊕
β,...,α
n
⊕
β)
=
ATS
−
IFWA
(α
1
,α
2
,...,α
n
)
⊕
β
(1.216)
Proof
Since
h
−
1
(μ
β
)), g
−
1
α
j
⊕
β
=
(
h
(μ
α
i
)
+
h
(g(
v
)
+
g(
v
β
))
(1.217)
α
i
then
ATS
−
IFWA
(α
1
⊕
β, α
2
⊕
β,...,α
n
⊕
β)
⎛
⎝
h
−
1
⎛
⎞
⎠
, g
−
1
⎛
⎞
⎠
⎞
⎠
n
n
w
i
h
(
h
−
1
w
i
g(g
−
1
⎝
⎝
=
(
h
(μ
α
i
)
+
h
(μ
β
)))
(g(
v
α
i
)
+
g(
v
β
)))
i
=
1
i
=
1
⎛
⎝
h
−
1
⎛
⎞
⎠
, g
−
1
⎛
⎞
⎠
⎞
⎠
n
n
⎝
⎝
(1.218)
=
w
i
(
h
(μ
α
i
)
+
h
(μ
β
))
w
i
(g(
v
α
i
)
+
g(
v
β
))
i
=
1
i
=
1
and
ATS
−
IFWA
(α
1
,α
1
,...,α
n
)
⊕
β
h
−
1
n
, g
−
1
n
=
w
i
h
(μ
α
i
)
w
i
g(
v
α
i
)
⊕
(μ
β
,
v
β
)
h
−
1
h
h
−
1
n
i
=
1
i
=
1
=
w
i
h
(μ
α
i
)
+
h
(μ
β
)
,
g
−
1
g
−
1
n
i
=
1
g
w
i
g(
v
α
i
)
+
g(
v
β
)
h
−
1
n
, g
−
1
n
i
=
1
=
w
i
h
(μ
α
i
)
+
h
(μ
β
)
w
i
g(
v
α
i
)
+
g(
v
β
)
h
−
1
n
, g
−
1
n
(1.219)
i
=
1
i
=
1
=
w
i
(
h
(μ
α
i
)
+
h
(μ
β
))
w
i
(g(
v
α
i
)
+
g(
v
β
))
i
=
1
i
=
1
which completes the proof.
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