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h
−
1
n
h
−
1
n
=
w
i
h
(μ
α
i
)
+
1
−
w
i
h
(μ
α
i
)
=
1
(1.208)
i
=
i
=
1
1
which completes the proof of Theorem 1.29.
Then we can investigate some desirable properties of the ATS-IFWA operator:
Theorem 1.30
(Xia et al. 2012c) If all
α
i
(
i
=
1
,
2
,...,
n
)
are equal, i.e.,
α
i
=
α
=
(μ
α
,
v
α
)
, for all
i
, then
−
(α
1
,α
2
,...,α
n
)
=
α
ATS
IFWA
(1.209)
Proof
Let
α
i
=
α
=
(μ
α
,
v
α
)
,wehave
n
⊕
ATS
−
IFWA
(α
1
,α
2
,...,α
n
)
=
ATS
−
IFWA
(α,α,...,α)
=
w
i
α
i
=
1
h
−
1
n
, g
−
1
n
=
w
i
h
(μ
α
)
w
i
g(
v
α
)
i
=
1
i
=
1
h
−
1
(μ
α
)) , g
−
1
=
(
h
(g(
v
α
))
=
α
(1.210)
Theorem 1.31
(Xia et al. 2012c) Let
β
i
=
(μ
β
i
,
v
β
i
)(
i
=
1
,
2
,...,
n
)
be a collec-
tion of IFVs, if
μ
α
i
≤
μ
β
i
and
v
≥
v
β
i
, for all
i
, then
α
i
ATS
−
IFWA
(α
1
,α
2
,...,α
n
)
≤
ATS
−
IFWA
(β
1
,β
2
,...,β
n
)
(1.211)
Proof
We have known that
h
(
t
)
=
g(
1
−
t
)
, and
g
:
[
0
,
1
]→
0
,
1
]
is a strictly
decreasing function, then
h
(
t
)
is a strictly increasing function. Since
μ
α
i
≤
μ
β
i
and
v
≥
v
β
i
, then we have
h
−
1
n
α
i
h
−
1
n
(μ
α
i
)
≤
(μ
β
i
)
w
i
h
w
i
h
(1.212)
i
=
1
i
=
1
g
−
1
n
≥
g
−
1
n
w
i
g(
v
α
i
)
w
i
g(
v
β
i
)
(1.213)
i
=
1
i
=
1
and thus,
S
(
ATS-IFWA
(α
1
,α
2
,...,α
n
))
≤
S
(
ATS-IFWA
(β
1
,β
2
,...,β
n
))
(1.214)
which completes the proof.
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