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Table 1.12
Intuitionistic fuzzy decision matrix
B
G
1
G
2
G
3
G
4
y
1
(
0
.
33
,
0
.
33
,
0
.
34
)
(
0
.
22
,
0
.
34
,
0
.
44
)
(
0
.
23
,
0
.
49
,
0
.
28
)
(
0
.
15
,
0
.
57
,
0
.
28
)
y
2
(
0
.
24
,
0
.
34
,
0
.
42
)
(
0
.
26
,
0
.
40
,
0
.
34
)
(
0
.
21
,
0
.
28
,
0
.
51
)
(
0
.
44
,
0
.
39
,
0
.
17
)
y
3
(
0
.
11
,
0
.
16
,
0
.
73
)
(
0
.
19
,
0
.
47
,
0
.
34
)
(
0
.
23
,
0
.
31
,
0
.
46
)
(
0
.
35
,
0
.
46
,
0
.
19
)
y
4
(
0
.
19
,
0
.
38
,
0
.
43
)
(
0
.
31
,
0
.
29
,
0
.
40
)
(
0
.
44
,
0
.
24
,
0
.
32
)
(
0
.
21
,
0
.
25
,
0
.
54
)
y
5
(
0
.
37
,
0
.
48
,
0
.
15
)
(
0
.
29
,
0
.
39
,
0
.
32
)
(
0
.
32
,
0
.
35
,
0
.
33
)
(
0
.
34
,
0
.
25
,
0
.
41
)
y
6
(
0
.
25
,
0
.
34
,
0
.
41
)
(
0
.
24
,
0
.
35
,
0
.
41
)
(
0
.
30
,
0
.
28
,
0
.
42
)
(
0
.
45
,
0
.
28
,
0
.
27
)
candidates. Project management is the application of knowledge, skills, tools, and
techniques to the implementation of project activities for the purpose of meeting
project requirements. The requirements of a project manager are not only morale,
but also proficiency in project management. Suppose that four attributes: (1)
G
1
(self-
confidence); (2)
G
2
(personality); (3)
G
3
(past experience); and (4)
G
4
(proficiency
in project management), are taken into consideration in the selection problem and
there exist six candidates
y
i
. Assume that the performance of
the alternative
y
i
with respect to the attribute
G
j
is measured by an IFV
b
ij
(
i
=
1
,
2
,...,
6
)
=
(μ
ij
,
v
ij
,π
ij
)
, and then we construct the intuitionistic fuzzy decision matrix
B
=
(
b
ij
)
6
×
4
(see Table
1.12
) (Xia et al. 2012b).
To get the optimal alternative(s), the following steps are given (Xia et al. 2012b):
(
=
,
,
,
)
Step 1
Considering all the attributes
G
j
j
1
2
3
4
are the benefit attributes,
(
=
,
,...,
)
the performance values of the alternatives
y
i
i
1
2
6
do not need normal-
ization.
Step 2
Aggregate all the performance values
r
ij
(
)
of the
i
th line, and get the overall performance value
r
i
corresponding to the alter-
native
y
i
by the GIFWBM (without of generalization, let
p
i
=
1
,
2
,
3
,
4
;
j
=
1
,
2
,...,
6
=
q
=
r
=
1
)
:
r
1
=
(
0
.
2061
,
0
.
4744
,
0
.
3195
),
r
2
=
(
0
.
3156
,
0
.
3532
,
0
.
3312
)
r
3
=
(
0
.
2583
,
0
.
3841
,
0
.
3576
),
r
4
=
(
0
.
2975
,
0
.
2673
,
0
.
4352
)
r
5
=
(
0
.
3270
,
0
.
3291
,
0
.
3439
),
r
6
=
(
0
.
3435
,
0
.
2997
,
0
.
3568
)
Step 3
Calculate the scores of all the alternatives:
S
(
r
1
)
=−
0
.
2683
,
S
(
r
2
)
=−
0
.
0376
,
S
(
r
3
)
=−
0
.
1259
S
(
r
4
)
=
0
.
0303
,
S
(
r
5
)
=−
0
.
0021
,
S
(
r
6
)
=
0
.
0439
Since
S
(
r
6
)>
S
(
r
4
)>
S
(
r
5
)>
S
(
r
2
)>
S
(
r
3
)>
S
(
r
1
)
then by Xu and Yager (2006)'s ranking method, we get the ranking of the IFVs:
r
6
>
r
4
>
r
5
>
r
2
>
r
3
>
r
1
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