Chemistry Reference
In-Depth Information
If
A.1
ˇ
S
/.N
1
C
ˇ
S
/
cN
2
A
4c
then
.3/
<L
D
is not empty, the unique
.1/
) and all the trajectories starting in
.3/
steady state is E
1
(since E
3
2 D
D
enter
.1/
.
2
D
A.1
ˇ
S
/.N
1
C
ˇ
S
/
cN
2
If L
D
,thenE
1
D
E
3
, and the equilibrium is located
.3/
from
.1/
.
along the boundary that separates
D
D
If L<
A.1
ˇ
S
/.N
1
C
ˇ
S
/
cN
2
, then the unique steady state is E
3
(since E
1
2
.3/
).
D
With regard to the stability of the equilibria, it is easy to realize that whenever
.3/
E
3
2 D
it is a stable equilibrium, because the Jacobian matrix of the map T
j
D
.3/
is
1
a0
N.1
a/ ˇ
S
:
J
.3/
D
Hence its eigenvalues 1
a and ˇ
S
are always less than one. In contrast, when
E
1
2 D
.1/
, its stability is not as easily determined because this requires the study of
the eigenvalues of the Jacobian matrix
0
@
aˇ
S
1
1
A
2c
p
c
.
.N
1/x
C
ˇ
S
S
/
aA.N
1/
2c
p
c
.
.N
1/x
C
ˇ
S
S
/
A
1
aN
C
J
.1/
N
1 aN C
ˇ
S
C Naˇ
S
2c
p
c
.
.N
1/x
C
ˇ
S
S
/
1
D
aA.N
1/
2c
p
c
.
.N
1/x
C
ˇ
S
S
/
A
evaluated at E
1
, which has the form
0
@
1
A
aN
.
N
1
C
2ˇ
S
/
2
.
N
1
C
ˇ
S
/
aˇ
S
.
2
.
1
ˇ
S
/
N
/
2
.
N
1
C
ˇ
S
/
1
N
1
J
.1/
.
E
1
/
D
:
aN
.
N
1
C
2ˇ
S
/
2
.
N
1
C
ˇ
S
/
N
aˇ
S
.
2
.
1
ˇ
S
/
N
/
2
.
N
1
C
ˇ
S
/
ˇ
S
C
Here the equilibrium condition
2c
r
A
S
1
D
2c S
1
c
.N
1/ x
1
C
ˇ
S
D
2A.N
1
C
ˇ
S
/=N
has been used. We can see that the stability of E
1
depends only on the parameters
N, a and ˇ
S
. Moreover, the matrix
J
.1/
.E
1
/ has the structure
A
11
;
A
12
NA
11
ˇ
S
C
NA
12
A
4c
the region
D
2
Note that at L
D
.3/
reduce to the line b
D
b
1
D
b
2
, which is a set of measure
2
.
zero in
R
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