Chemistry Reference
In-Depth Information
If A.1 ˇ S /.N 1 C ˇ S /
cN 2
A
4c then
.3/
<L
D
is not empty, the unique
.1/ ) and all the trajectories starting in
.3/
steady state is E 1 (since E 3
2 D
D
enter
.1/ . 2
D
A.1 ˇ S /.N 1 C ˇ S /
cN 2
If L D
,thenE 1 D E 3 , and the equilibrium is located
.3/ from
.1/ .
along the boundary that separates
D
D
If L< A.1 ˇ S /.N 1 C ˇ S /
cN 2
, then the unique steady state is E 3 (since E 1 2
.3/ ).
D
With regard to the stability of the equilibria, it is easy to realize that whenever
.3/
E 3
2 D
it is a stable equilibrium, because the Jacobian matrix of the map T j D .3/
is
1 a0
N.1 a/ ˇ S
:
J .3/
D
Hence its eigenvalues 1 a and ˇ S are always less than one. In contrast, when
E 1 2 D
.1/ , its stability is not as easily determined because this requires the study of
the eigenvalues of the Jacobian matrix
0
@
S
1
1
A
2c p c . .N 1/x C ˇ S S /
aA.N 1/
2c p c . .N 1/x C ˇ S S /
A
1
aN
C
J .1/
N 1 aN C
ˇ S C Naˇ S
2c p c . .N 1/x C ˇ S S / 1
D
aA.N 1/
2c p c . .N 1/x C ˇ S S /
A
evaluated at E 1 , which has the form
0
@
1
A
aN . N 1 C S /
2 . N 1 C ˇ S /
S . 2 . 1 ˇ S / N /
2 . N 1 C ˇ S /
1
N 1
J .1/ . E 1 /
D
:
aN . N 1 C S /
2 . N 1 C ˇ S /
N S . 2 . 1 ˇ S / N /
2 . N 1 C ˇ S /
ˇ S C
Here the equilibrium condition
2c r A
S 1 D 2c S 1
c .N 1/ x 1 C ˇ S
D 2A.N 1 C ˇ S /=N
has been used. We can see that the stability of E 1 depends only on the parameters
N, a and ˇ S . Moreover, the matrix J .1/ .E 1 / has the structure
A 11
;
A 12
NA 11 ˇ S
C NA 12
A
4c the region D
2 Note that at L
D
.3/ reduce to the line b
D
b 1 D
b 2 , which is a set of measure
2 .
zero in R
 
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