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1
0.8
0.6
0.4
0.2
0
−0.2
−0.4
0
0.01
0.02
0.03
0.04
0.05
0.06
0.07
0.08
0.09
0.1
time in sec. solid: y due to y(0), dash−dot: IVCed
Figure 3.41: Simulation result of the IVC.
The response of the system is shown in Figure 3.41.
Solution 2:
In view of equation (3.77), let
T (s) = − (s + 1000)7.143 × 10 −6 s 2
I v = − S(s)
,
(3.79)
s +71.43
so that the effect of initial values is totally canceled out. However, this transfer
function is not causal. We can make I v (s) causal by including additional (fast)
poles. Then I v can be expressed as
I v (s)=− S(s)
T (s)
1
additional (fast) poles
−6 s 3 +0.007143s 2
s +71.43
= − 10
1
additional (fast) poles .
(3.80)
Tak ing I v into consideration, the transfer function from the initial position
value to plant output is,
y
y(0) = S + I v T = S(1−
1
additional (fast) poles ).
(3.81)
By selecting the additional poles to be a few times faster than those of S(s)
with a damping ratio close to 1, the effect of y(0) on y is dominated by these
fast poles and diminishes quickly.
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