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u
T
R
d
u
d
ζ
=
u
T
d
d
ζ
Du
+
α
u
T
d
D
d
ζ
u
+
α
u
T
D
d
u
d
ζ
u
T
R
−
α
u
T
D
d
u
d
=
u
T
d
d
Du
+
α
u
T
d
D
d
u
(6.46)
ζ
ζ
ζ
=
u
T
d
d
ζ
Du
+
α
u
T
d
D
d
ζ
0
u
Hence,
u
T
d
d
ζ
(
d
Du
/
d
ζ)
u
=−
α
u
T
Du
Considering that
=
2
I
n
d
D
d
ζ
0
=
2
J
(6.47)
0
T
−
1
and
u
T
Du
=
2
(
1
−
ζ
)
+
2
ζ
x
T
x
then
x
T
x
d
d
ζ
1
(
1
−
ζ )
+
ζ
x
T
x
−
=−
α
(6.48)
This equation can be rewritten as
d
d
ζ
+
=−
α
1
=−
αφ (
,
ζ )
ζ
6.3.2 Eigenvector Derivative
From eq. (6.46) it follows for the
i
th eigenvector
u
i
associate with the eigen-
value
α
i
:
α
i
d
ζ
d
u
i
d
ζ
d
Du
i
+
α
i
d
D
d
ζ
(
R
−
α
i
D
)
=
u
i
(6.49)
and
D
−
1
R
−
α
i
I
n
+
1
d
u
i
d
d
α
i
d
u
i
+
α
i
D
−
1
d
D
d
=
u
i
ζ
ζ
ζ
Define
D
−
1
R
H
=
−
α
i
I
n
+
1
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