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σ
2
=
σ
2
2
1
+
(
1
−
ζ )
+
o
(
1
−
ζ )
i
2
ζ
i
2
(6.41)
which is a good approximation in a neighborhood of
ζ
=
1(DLS).For
ζ
=
1
these bounds have the lowest values with respect to
ζ
(i.e.,
σ
2
i
/
2
∀
i
). Considering
the change of variable
µ
=
1
−
ζ
, these bounds can be analyzed for increasing
µ
(from zero on); that is, for problems with decreasing
ζ
but still close to DLS:
≤
σ
2
σ
2
i
2
i
−
1
(
1
+
µ)
≤
α
i
(
1
+
µ)
∀
i
=
2,
...
,
n
(6.42)
2
All bounds increase linearly with
, which implies that all the eigenvalues of
K
but the smallest and largest ones
1
increase linearly with
µ
. However, the increase
rate is not the same. Obviously, larger eigenvalues increase more than do smaller
eigenvalues.
About the TLS case
µ
ζ
=
0
.
5, the bounds can be approximated as
σ
2
i
2
ζ
=
σ
i
1
−
2
(ζ
−
0
.
5
)
+
o
(ζ
−
0
.
5
)
2
(6.43)
By using the substitution
µ
=
0
.
5
−
ζ
, the approximation around the TLS case
becomes
σ
2
≤
σ
2
(
1
+
2
µ)
≤
α
i
(
1
+
2
µ)
∀
i
=
2,
...
,
n
(6.44)
i
i
−
1
and the same analysis as for DLS can be repeated here in a neighborhood of
ζ
=
0
.
5 (i.e., around
µ
=
0).
6.3 ANALYSIS OF THE DERIVATIVE OF THE EIGENSYSTEM
OF GeTLS EXIN
6.3.1 Eigenvalue Derivative
From eq. (6.2), repeated here:
Ru
=
α
Du
(6.45)
it follows, by deriving both sides with respect to
ζ
:
R
d
u
d
d
d
d
D
d
D
d
u
d
=
Du
+
α
u
+
α
ζ
ζ
ζ
ζ
1
This Taylor approximation analysis cannot take these two extreme cases into account because only
one bound is given for each case.
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