Chemistry Reference
In-Depth Information
In Eq. (53), one has, for example,
e E / ( k B T ) δ ε α
E V (1)
π
V (1)
γ
ε γ +
E
α,γ
Z b
e E ν k λ ,... / ( k B T ) δ ε α
ω k
π
=
ε γ +
Z b
ν k λ ,...
k λ
( k )
M ( k )
(1)
γα ·
(1)
αγ
M
×
·
e E ν k λ ,... / ( k B T ) δ ε α
ω k
π
+
ε γ
Z b
ν k λ ,...
k λ
( k )
( k )
(1)
γα ·
(1)
αγ
M +
×
·
M
(165)
+
After averaging over phonon populations,
1
Z b
1
e ω k / ( k B T )
e E ν k λ ,... / ( k B T ) ν k λ
ν k λ =
n k λ =
n k =
(166)
1
ν k λ ,...
this becomes
8 MN
k λ
π
×
×
[ k
e k λ ]
ω k
[ k
e k λ ]
ω k
(1)
(1)
αγ
·
γα ·
δ ε α
ω k n k
×
ε γ +
[ k
e k λ ]
ω k
×
[ k
e k λ ]
ω k
×
(1)
γα ·
(1)
+
αγ ·
δ ε α
ω k ( n k +
1)
×
ε γ
(167)
Further simplifications can be achieved using
k
e k t 1
×
k e k t 2
(168)
and, for the summation over the two transverse polarizations,
( k
·
a )( k
·
b )
( e k t ·
a )( e k t ·
b )
=
( a
·
b )
(169)
k 2
t
=
t 1 ,t 2
with a
=
b
=
e x , and then with e y. Averaging over the directions of the vector k :
k 2
3
( k
·
a )( k
·
b )
=
( a
·
b )
(170)
 
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