Civil Engineering Reference
In-Depth Information
0.85f' c
0.003
C
a= β 1 c
c
d
d - a
2
T
ε
t
b
Strain
Stress
ε
t ≥ 0.005 Tension control
φ
= 0.9
ε
t = 0.004 Minimum for beams and slabs
φ
= 0.817
ε
t = 0.002 Balanced condition
φ
= 0.65 (See chapter 5 Columns)
ε
t ≤ 0.002 Compression controls
φ
= 0.65 (See chapter 5 Columns)
0.005 >
ε
t < 0.002 Transition
C = 0.85 f' c
T = F s A s ≤ F y A s
T = C
M n = C [d -a/2] = T (d-a/2)
Figure 3-2 Code Strain Distribution and Stress Block for Nominal Strength Calculations
3.4
DESIGN FOR FLEXURAL REINFORCEMENT
Similar to developing the sizing equation, a simplified equation for the area of tension steel A s can be derived
using the strength design approach developed in Chapter 6 of Reference 3.8. An approximate linear relationship
between R n and
ρ
can be described by an equation in the form M n /bd 2 =
ρ
(constant), which readily converts to
A s = M u /
φ
d(constant). This linear equation for A s is reasonably accurate up to about two-thirds of the maximum
ρ
. For › = 4000 psi and
ρ
= 0.0125 (60%
ρ max ), the constant for the linear approximation is :
 
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