Civil Engineering Reference
In-Depth Information
0.85f'
c
0.003
C
a=
β
1
c
c
d
d -
a
2
T
ε
t
b
Strain
Stress
ε
t
≥ 0.005 Tension control
φ
= 0.9
ε
t
= 0.004 Minimum for beams and slabs
φ
= 0.817
ε
t
= 0.002 Balanced condition
φ
= 0.65 (See chapter 5 Columns)
ε
t
≤ 0.002 Compression controls
φ
= 0.65 (See chapter 5 Columns)
0.005 >
ε
t
< 0.002 Transition
C = 0.85
f'
c
T = F
s
A
s
≤ F
y
A
s
T = C
M
n
= C [d -a/2] = T (d-a/2)
Figure 3-2 Code Strain Distribution and Stress Block for Nominal Strength Calculations
3.4
DESIGN FOR FLEXURAL REINFORCEMENT
Similar to developing the sizing equation, a simplified equation for the area of tension steel A
s
can be derived
using the strength design approach developed in Chapter 6 of Reference 3.8. An approximate linear relationship
between R
n
and
ρ
can be described by an equation in the form M
n
/bd
2
=
ρ
(constant), which readily converts to
A
s
= M
u
/
φ
d(constant). This linear equation for A
s
is reasonably accurate up to about two-thirds of the maximum
ρ
. For › = 4000 psi and
ρ
= 0.0125 (60%
ρ
max
), the constant for the linear approximation is :
Search WWH ::
Custom Search