Civil Engineering Reference
In-Depth Information
˜
t
in
the damage in the tension area is analysed. The effective tensile stress
σ
the tension area is expressed by:
σ
t
(
)
σ
=
=
E
εσ
,
≥
0
,
D
≥
0
[4.6]
t
t
t
1
−
D
where
D
and
E
are respectively the degree of damage and the elastic
modulus;
σ
t
are respectively the strain and stress of the extreme
tension fi bre at the bottom of the concrete beam.
The effective compressive stress
ε
t
and
˜
c
in the compressive area is given by:
σ
(
)
σσ
==
E
εσ
,
≤
0
D
=
0
[4.7]
c
c
c
c
where
c
are respectively the strain and stress of the extreme com-
pression fi bre at the top of the concrete beam.
ε
c
and
σ
σ
, where
k
˜
When the effective stress
σ
>
0 (tension stress), we have
D
=
k
˜
is the damage modulus. When
σ
≤
0, we have
D
=
0. Based on the strain
equivalence hypothesis, the following is obtained:
σ
E
k
ε
⎛
⎝
⎞
⎠
⎛
⎝
⎞
⎠
(
)
(
)
σ
=−
1
D
σ
=−
1
D E
ε
=−
1
E
ε
=−
1
E
ε
[4.8]
k
where
are respectively the strain and stress of the concrete matrix.
If the beam is in the elastic stage, the degree of damage in the concrete
ε
and
σ
D
. After the elastic stage, the stress state of the tension
zone tends to be elasto-plastic due to the redistribution of stress before
cracking. The correlation between
=
0, then
σ
=
E
ε
ε
and
σ
may be derived from Eq. [4.8]
and expressed by:
d
d
σ
ε
2
E
k
2
ε
=−
E
[4.9]
At the peak value of stress, the fi rst derivative of stress should be equal
to zero as described in Eq. [4.10]:
d
d
σ
=
0
[4.10]
ε
In this event, the critical cracking stress is
cr
and the degree of damage
D
is equal to
D
cr
. From Eq. [4.9] and [4.10], we get
E
σ
k
ε =
2
. Replacing
E
ε
k
=
4
.
in Eq. [4.8] gives the critical cracking stress
σ
cr
σ
,
k
(
)
When
D
=
σ
cr
can be evaluated as
σ
cr
==−
1
DDk
, from which
cr
cr
k
4
˜
cr
may
D
cr
=
0.5 is obtained. Therefore, the effective critical cracking stress
σ
be expressed as:
Search WWH ::
Custom Search