Civil Engineering Reference
In-Depth Information
˜ t in
the damage in the tension area is analysed. The effective tensile stress
σ
the tension area is expressed by:
σ
t
(
)
σ
=
=
E
εσ
,
0
,
D
0
[4.6]
t
t
t
1
D
where D and E are respectively the degree of damage and the elastic
modulus;
σ t are respectively the strain and stress of the extreme
tension fi bre at the bottom of the concrete beam.
The effective compressive stress
ε t and
˜ c in the compressive area is given by:
σ
(
)
σσ
==
E
εσ
,
0
D
=
0
[4.7]
c
c
c
c
where
c are respectively the strain and stress of the extreme com-
pression fi bre at the top of the concrete beam.
ε
c and
σ
σ , where k
˜
When the effective stress
σ
>
0 (tension stress), we have D
=
k
˜
is the damage modulus. When
σ
0, we have D
=
0. Based on the strain
equivalence hypothesis, the following is obtained:
σ
E
k
ε
(
)
(
)
σ
=−
1
D
σ
=−
1
D E
ε
=−
1
E
ε
=−
1
E
ε
[4.8]
k
where
are respectively the strain and stress of the concrete matrix.
If the beam is in the elastic stage, the degree of damage in the concrete
ε
and
σ
D
. After the elastic stage, the stress state of the tension
zone tends to be elasto-plastic due to the redistribution of stress before
cracking. The correlation between
=
0, then
σ
=
E
ε
ε
and
σ
may be derived from Eq. [4.8]
and expressed by:
d
d
σ
ε
2
E
k
2
ε
=−
E
[4.9]
At the peak value of stress, the fi rst derivative of stress should be equal
to zero as described in Eq. [4.10]:
￿ ￿ ￿ ￿ ￿ ￿
d
d σ
=
0
[4.10]
ε
In this event, the critical cracking stress is
cr and the degree of damage
D is equal to D cr . From Eq. [4.9] and [4.10], we get E
σ
k
ε = 2 . Replacing E
ε
k
= 4 .
in Eq. [4.8] gives the critical cracking stress
σ cr
σ ,
k
(
)
When D
=
σ cr can be evaluated as
σ cr
==−
1
DDk
, from which
cr
cr
k
4
˜ cr may
D cr
=
0.5 is obtained. Therefore, the effective critical cracking stress
σ
be expressed as:
 
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