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Therefore,
ʔ
(
A
)
≤
inf
n
≥
0
ʘ
(
∼
n
(
A
))
=
ʘ
((
∩
n
≥
0
∼
n
)(
A
))
=
ʘ
(
∼
ˉ
(
A
))
.
Using Theorem
3.5
(1) again, we obtain (
3.12
).
By symmetry we also have that if
t
a
−ₒ
a
−ₒ
ʘ
then there is some
ʔ
with
s
ʔ
∼
ˉ
)
†
ʘ
.
and
ʔ
(
Let
≺
be the largest probabilistic simulation, called probabilistic similarity, and
≺∩≺
−
1
, called
simulation equivalence
.
In general, simulation equivalence is coarser than bisimilarity. However, for reactive
pLTSs, the two relations do coincide. Recall that in a reactive pLTS, for each state
s
and action
a
there is at most one distribution
ʔ
with
s
be the kernel of probabilistic similarity, i.e.
a
−ₒ
ʔ
. To prove that result,
we need a technical lemma.
†
Lemma 3.3
Let
R
be a preorder on a set S and ʔ
,
ʘ
∈
D
(
S
)
.Ifʔ
R
ʘ and
†
ʔ then ʔ
(
C
)
ʘ
R
=
ʘ
(
C
)
for all equivalence classes C with respect to the kernel
R
∩
R
−
1
of
R
.
R
∩
R
−
1
. For any
s
Proof
Let us write
≡
for
∈
S
, let [
s
]
≡
be the equivalence class
{
∈
|
R
∧
R
}
that contains
s
. Let
A
s
be the set
t
S
s
t
t
s
. It is easy to see that
R
(
s
)
={
t
∈
S
|
s
R
t
}
={
t
∈
S
|
s
R
t
∧
t
R
s
}{
t
∈
S
|
s
R
t
∧
t
R
s
}
=
[
s
]
≡
A
s
where
stands for a disjoint union. Therefore, we have
ʔ
(
R
(
s
))
=
ʔ
([
s
]
≡
)
+
ʔ
(
A
s
)
and
ʘ
(
R
(
s
))
=
ʘ
([
s
]
≡
)
+
ʘ
(
A
s
)
.
(3.13)
We now check that both
R
(
s
) and
A
s
are
R
-closed sets, that is
R
(
R
(
s
))
ↆ
R
(
s
)
and
R
(
A
s
)
ↆ
A
s
. Suppose
u
∈
R
(
R
(
s
)). Then there exists some
t
∈
R
(
s
) such that
t
R
u
, which means that
s
R
t
and
t
R
u
. As a preorder
R
is a transitive relation. So we
have
s
R
u
that implies
u
∈
R
(
s
). Therefore we can conclude that
R
(
R
(
s
))
ↆ
R
(
s
).
Suppose
u
∈
R
(
A
s
). Then there exists some
t
∈
A
s
such that
t
R
u
, which means
that
s
R
t
,
t
R
s
and
t
R
u
. As a preorder
R
is a transitive relation. So we have
s
R
u
. Note that we also have
u
R
s
. Otherwise we would have
u
R
s
, which
means, together with
t
R
u
and the transitivity of
R
, that
t
R
s
, a contradiction to the
hypothesis
t
R
s
. It then follows that
u
∈
A
s
and then we conclude that
R
(
A
s
)
ↆ
A
s
.
†
ʘ
and
ʘ
†
ʔ
,
We have verified that
R
(
s
) and
A
s
are
R
-closed sets. Since
ʔ
R
R
R
≤
R
R
≤
we apply Theorem
3.5
(2) and obtain that
ʔ
(
(
s
))
ʘ
(
(
s
)) and
ʘ
(
(
s
))
R
ʔ
(
(
s
)), that is
ʔ
(
R
(
s
))
=
ʘ
(
R
(
s
))
.
(3.14)
Similarly, using the fact that
A
s
is
R
-closed we obtain that
ʔ
(
A
s
)
=
ʘ
(
A
s
)
(3.15)
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