Information Technology Reference
In-Depth Information
As a consequence, the finite generability result, Theorem 6.9 , specialises to
extreme derivatives.
Corollary 6.4
Let
{
ep 1 , ... , ep k }
be the finite set of extreme policies of a finitary
ˉ -respecting pLTS
S , ʩ ˄ ,
R
. For any state s and subdistribution ʔ in the pLTS,
s
ʔ if and only if ʔ
∈{
Der ep i
( s )
|
1
i
k
}
.
Proof O n e direction follows immediately from the previous lemma. Conversely,
suppose s
= 1 i n p i ·
Der dp i ( s ) for some finite
collection of derivative policies dp i , where we can assume that each p i
ʔ . By Theorem 6.9 , ʔ
0. Because
˄
−ₒ
ʔ is stable, that is s
, we show that each derivative policy
dp i can be transformed into an extreme policy ep i such that Der ep i ( s )
for every s
ʔ
=
Der dp i ( s ),
from which the result will follow.
First, note it is sufficient to define ep i on the set of states t accessible from s via
the policy dp i ; on the remaining states in S ep i can be defined arbitrarily, so as to
satisfy the requirements of Definition 4.8. So consider the derivation of Der dp i ( s )as
in Definition 6.4 , determined by dp i and suppose t
ʔ k
for some k
0. There
are three cases:
(i) Suppose t
˄
−ₒ
ʔ k
, and therefore by definition
dp i ( t ) is defined. So in this case we let ep i ( t ) be the same as dp i ( t ).
(ii) Suppose t
. Since ʔ is stable we know t
ˉ
−ₒ
˄
−ₒ
,
and therefore dp i ( t ) is not defined. Here we choose ep i ( t ) arbitrarily so as to
satisfy t
, in which case, since the pLTS is ˉ -respecting, we know t
ˉ
−ₒ
ep i ( t ).
(iii) Otherwise we leave ep i ( t ) undefined.
By definition, ep i is an extreme policy since it satisfies conditions (a) and (b) in
Definition 4.8 and by construction Der ep i ( s )
This corollary gives a useful method for calculating the set of extreme derivatives
of a given state, and therefore of the result of applying a test to a process.
=
Der dp i ( s ).
Example 6.11 Consider again Fig. 4.4, discussed in Example 6.9 , where we have
the ˉ -respecting pLTS obtained by applying the test a.ˉ to the process Q 2 . There are
only two extreme policies for this pLTS, denoted by ep 0 and ep 1 . They differ only
for the state s 1 , with ep 0 ( s 1 )
=
ʘ 0 and ep 1 ( s 1 )
=
ʘ 1 . The discussion in Example 6.9
explained how
1
2 ˉ. 0
By Corollary 6.4 , we know that every possible extreme derivative of [[[ T
1
2 s 3 +
Der ep 0 ( s 1 )
=
ˉ. 0
Der ep 1 ( s 1 )
=
| Act Q 2 ]] ]
takes the form
1
2 s 3 +
2 ˉ. 0
1
q
·
ˉ. 0
+
(1
q )
·
ˉ and $( 2 s 3 +
2 ˉ it follows that
1
1
for some 0
q
1. Since $( ˉ )
=
2 ˉ )
=
q ˉ
1
2 ,1 .
d ( T , Q 2 )
A
=
| q
 
Search WWH ::




Custom Search