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1
q i ( p i o i +
p j p ji o ji )
o i =
j J
for each i
0.
It can be checked by arithmetic that q i , ʔ i , o i have the required properties,
I , except that ʔ i and o i are chosen arbitrarily in case q i =
viz. that i I q i =
= i I q i o i and that
1, that o
˄
ˆ
ʔ j
s
p i ·
s
+
p j ·
i I
j J
˄
ʔ ji
p i ·
s
+
p j ·
p ji ·
by ( 5.17 ) and Lemma 5.4
i
I
j
J
i
I
=
q i ·
ʔ i .
i
I
Finally, it follows from ( 5.15 ) and ( 5.19 ) that o i A
( T i , ʔ i ) for each i
I .
(b) Let
ʔ ( s j ). Without loss of generality we may as-
sume that J is a nonempty finite set disjoint from I . Using the condition that
A
ʔ
={
s j } j J and r j =
( T , ʔ ):
=
Exp ʔ A
( T , __), if o
A
( T , ʔ ) then
r j o j
=
o
(5.20)
j
J
o j A
( T , s j ) .
(5.21)
For each j
J , we know by the induction hypothesis that
˄
ʔ ji
s j
q ji ·
(5.22)
i
I
o j =
q ji o ji
(5.23)
i I
o ji A
( T i , ʔ ji )
(5.24)
{ q ji } i I with i I q ji =
for some
1. Thus let
q i =
r j q ji
j J
1
q i
r j q ji · ʔ ji
ʔ i =
j J
1
q i
r j q ji o ji
o i =
j J
again choosing ʔ i and o i arbitrarily in case q i =
0. As in the first case, it can be
shown by arithmetic that the collection r i , ʔ i , o i has the required properties.
 
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