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1
q
i
(
p
i
o
i
+
p
j
p
ji
o
ji
)
o
i
=
j
∈
J
for each
i
0.
It can be checked by arithmetic that
q
i
,
ʔ
i
,
o
i
have the required properties,
∈
I
, except that
ʔ
i
and
o
i
are chosen arbitrarily in case
q
i
=
viz. that
i
∈
I
q
i
=
=
i
∈
I
q
i
o
i
and that
1, that
o
˄
⃒
ˆ
ʔ
j
s
p
i
·
s
+
p
j
·
i
∈
I
j
∈
J
˄
⃒
ʔ
ji
p
i
·
s
+
p
j
·
p
ji
·
by (
5.17
) and Lemma
5.4
i
∈
I
j
∈
J
i
∈
I
=
q
i
·
ʔ
i
.
i
∈
I
Finally, it follows from (
5.15
) and (
5.19
) that
o
i
∈
A
(
T
i
,
ʔ
i
) for each
i
∈
I
.
(b) Let
ʔ
(
s
j
). Without loss of generality we may as-
sume that
J
is a nonempty finite set disjoint from
I
. Using the condition that
A
ʔ
={
s
j
}
j
∈
J
and
r
j
=
(
T
,
ʔ
):
=
Exp
ʔ
A
(
T
, __), if
o
∈
A
(
T
,
ʔ
) then
r
j
o
j
=
o
(5.20)
j
∈
J
o
j
∈
A
(
T
,
s
j
)
.
(5.21)
For each
j
∈
J
, we know by the induction hypothesis that
˄
⃒
ʔ
ji
s
j
q
ji
·
(5.22)
i
∈
I
o
j
=
q
ji
o
ji
(5.23)
i
∈
I
o
ji
∈
A
(
T
i
,
ʔ
ji
)
(5.24)
{
q
ji
}
i
∈
I
with
i
∈
I
q
ji
=
for some
1. Thus let
q
i
=
r
j
q
ji
j
∈
J
1
q
i
r
j
q
ji
·
ʔ
ji
ʔ
i
=
j
∈
J
1
q
i
r
j
q
ji
o
ji
o
i
=
j
∈
J
again choosing
ʔ
i
and
o
i
arbitrarily in case
q
i
=
0. As in the first case, it can be
shown by arithmetic that the collection
r
i
,
ʔ
i
,
o
i
has the required properties.
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