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Proof
We first prove the case
ʱ
=
˄
. For each
i
∈
I
there is a number
k
i
such that
˄
−ₒ
˄
−ₒ
˄
−ₒ ···
˄
−ₒ
ʔ
i
. Let
k
ʔ
i
=
ʔ
i
0
ʔ
i
1
ʔ
i
2
ʔ
ik
i
=
=
max
{
k
i
|
i
∈
I
}
,
˄
−ₒ
using that
I
is finite. Since we have
Φ
(
S
), we can add spurious
transitions to these sequences, until all
k
i
equal
k
. After this preparation the lemma
follows by
k
applications of the linearity of the lifting operation (cf. Definition
5.3
),
taking
Φ
for any
Φ
∈
D
˄
−ₒ
for
R
.
Act
now follows by one more application of the linearity of lifting
operation, this time with
The case
ʱ
∈
a
−ₒ
R
=
, preceded and followed by an application of the
case
ʱ
=
˄
.
ʱ
−ₒ
ʱ
⃒
s
)
†
Φ and ʔ
ʔ
. Then Φ
Φ
for some Φ
such
Lemma 5.5
Suppose ʔ
(
that ʔ
(
s
)
†
Φ
.
Proof
First
ʔ
(
s
)
†
Φ
means that
ʔ
=
p
i
·
s
i
,
s
i
s
Φ
i
,
Φ
=
p
i
·
Φ
i
;
(5.2)
i
∈
I
i
∈
I
ʱ
−ₒ
ʔ
means
also
ʔ
ʱ
−ₒ
ʘ
j
,
ʔ
=
ʔ
=
q
j
·
t
j
,
t
j
q
j
·
ʘ
j
,
(5.3)
j
∈
J
j
∈
J
and we can assume without loss of generality that all the coefficients
p
i
,
q
j
are
nonzero. Now define
I
j
={
i
∈
I
|
s
i
=
t
j
}
and
J
i
={
j
∈
J
|
t
j
=
s
i
}
, so that
trivially
{
(
i
,
j
)
|
i
∈
I
,
j
∈
J
i
}={
(
i
,
j
)
|
j
∈
J
,
i
∈
I
j
}
(5.4)
and note that
ʔ
(
s
i
)
=
q
j
and
ʔ
(
t
j
)
=
p
i
(5.5)
j
∈
J
i
i
∈
I
j
Because of (
5.5
)wehave
q
j
ʔ
(
s
i
)
·
Φ
=
p
i
·
Φ
i
=
p
i
·
Φ
i
i
∈
I
i
∈
I
j
∈
J
i
p
i
·
q
j
ʔ
(
s
i
)
·
=
Φ
i
i
∈
I
j
∈
J
i
Now for each
j
in
J
i
we know that in fact
t
j
=
s
i
, and so from the middle parts of
ʱ
⃒
s
)
†
Φ
ij
. Lemma
5.4
yields
(
5.2
) and (
5.3
) we obtain
Φ
i
Φ
ij
such that
ʘ
j
(
p
i
·
q
j
ʔ
(
s
i
)
·
ʱ
⃒
Φ
=
Φ
Φ
ij
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