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In-Depth Information
In case P
sCSP , a statement P S Q cannot always be established by a simulation
R
such that [[ P ]]
R
[[ Q ]] .
Example 5.14
Compare the processes P
=
a 2
b and P
P . Note that [[ P ]] is the
1
1
distribution
2 a
+
2 b , whereas [[ P
P ]] is the point distribution P
P . The relation
R
given by
( 2 a +
1
( P P )
R
2 b )
a R a
b R b
0
R
0
˄
−ₒ
( 2 a
1
is a simulation, because the ˄ step P
P
+
2 b ) can be matched by the idle
˄
transition ( 2 a
1
2 b )
( 2 a
1
2 b ), and we have ( 2 a
1
2 b )
( 2 a
1
2 b ). Thus
+
+
+
R
+
s ) [[ P ]], and therefore P P S P .
This t ype o f rea soning does not apply to the oth er dire ction. A ny sim ulation
s ( 2 a +
1
( P P )
2 b )
=
[[ P ]], hence [[ P P ]] (
R
with ( 2 a
1
P
+
2 b )
R
P would have to satisfy a
R
P
P an d b
R
P
P . However,
a
−ₒ
the move a
0 cannot be mat ched by the p ro cess P
P , as the only transition
˄
−ₒ
1
2 b ), and only half of that distribution
can match the a move. As a consequence, no such simulation exists, and we find that
[[ P ]] (
( 2 a
the latter process can do is P
P
+
s ) [[ P
S P
P ]] does not hold. Nevertheless, we still have P
P . Here, the
˄
˄
transition
from Definition 5.5 comes to the rescue. As [[ P P ]]
[[ P ]] and
s ) [[ P ]], we obtain P S P P .
Example 5.15
[[ P ]] (
Let P
=
a 2
b and Q
=
P
P . We can establish that P
S Q
s ) [[ Q ]] that comes from the following observations:
because [[ P ]] (
1
2 a
1
2 b
1. [[ P ]]
=
+
1
2 ( 2 a
1
1
2 ( 2 a
1
2. [[ Q ]]
=
a
+
2 a
b )
+
b
+
2 b
b )
s ( 2 a
1
2 a
3. a
a
+
b )
s ( 2 a
1
4. b
b
+
2 b
b ).
This kind of reasoning does not apply to
FS . For example, we have
FS ( 1
1
2 a
a
2 a
a
+
b )
because the state on the left hand side can refuse to do action b while the distribution
on the right hand side cannot. Indeed, it holds that Q
FS P .
Because of the asymmetric use of distributions in the definition of simulations
it is not immediately obvious that
S and
FS are actually preorders (reflexive and
transitive relations) and hence,
FS are equivalence relations. In order to
show this, we first need to establish some properties of
S and
s and
FS .
Suppose i I p i =
ʱ
Lemma 5.4
1 and ʔ i
Φ i for each i
I , with I a finite
index set. Then
ʱ
p i ·
ʔ i
p i ·
Φ i
i I
i I
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