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Fig. 5.7 Two simulation equivalent processes
FS are called (forward) simulation
equivalence and failure simulation equivalence , denoted
The equivalences generated by
S and
S and
FS , respe ct ively.
If P
sCSP , that is if P is a state in the pLTS of pCSP and so [[ P ]]
=
P , then
to establish P
S Q it is sufficient to exhibit a simul a tion between the state P and the
distribution [[ Q ]], because trivially s
s ) ʔ .
Example 5.13 Consider the two processes P i i n Fig. 5.7 . To show P 1 S P 2 it is
sufficient to exhibit a simulation
s ʔ implies s (
R
such that s 0 R
t 0 . Let
R
sCSP
× D
( sCSP )be
defined by
s 0 R
t 0
s 1 R
ʔ t
s 2 R
t 3
s 3 R
t 3
0
R
0
1
where ʔ t is the two-point distribution mapping both t 1 and t 2 to the probability
2 .
Then it is straightforward to check that it satisfies the requirements of a simulation:
the only nontrivial requirement is that ʔ 1 R
ʔ 2 . But this follows from the fact that
1
2 ·
1
4 ·
1
4 ·
ʔ 1 =
s 1 +
s 2 +
s 3
1
1
1
ʔ 2 =
2 ·
ʔ t +
4 ·
t 3 +
4 ·
t 3 .
As another example reconsider R 1 =
a.c from Fig. 5.5 ,
where for convenience we use process terms to denote their semantic interpretations.
It is easy to see that R 1 S R 2 because of the simulation
a. ( b 2
c ) and R 2 =
a.b 2
R 1 R
R
R
0
R
0
[[ R 2 ]]
b
b
c
c
a
−ₒ
a
−ₒ
The transition R 1
( b 2
c ) is matched by the transition R 2
( b 2
c ) with
( b 2
R
( b 2
c )
c ).
Similarly,
( a 2
c )
( b 2
c )
S ( a
b ) 2
c because it is possible to find a
simulation between the state ( a 2 c )
( b 2 c ) and the distribution ( a b ) 2 c .
 
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