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3. The probability that the project will finish before day 30 . This probability
is the same as the probability of finishing by the end of day 29.
Z =( 29 32 )∕ 2
.
972 =− 1
.
01
0, take the probability that corresponds to the positive
value of Z and then subtract it from 1.0 (100%):
When Z
<
Pr ( T s
29 )= 1 0
.
844 = 0
.
156 = 15
.
6 %
SeeFigure11.4.
Figure 11.4 Solution to example 11.1, part 3
4. The probability that the project will finish on day 32 .
Pr ( T s = 32 )= Pr ( T s
32 )− Pr ( T s
31 )
We already calculated Pr ( T s
32 )= 0
.
5 = 50 % (part 1). For
Pr ( T s
31 ) ,
Z =( 31 32 )∕ 2
.
972 =− 0
.
34
Pr ( T s
31 )= 1 0
.
633 = 0
.
367 = 36
.
7 %
and
Pr ( T s = 32 )= Pr ( T s
32 )− Pr ( T s
31 )= 50 %− 36
.
7 %= 13
.
3 %
SeeFigure11.5.
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