Precedence Networks - Construction Project Scheduling and Control - page 107

7. Activity A must finish before B can start. LF = 7. Use the earlier of
LS = 7 − 2 = 5 and LS (for C) − 1-day lag = 1 − 1 = 0. We choose
LS = 0.
8. The critical path is the start of A, all of C, the end of E, and all of G
(Figure 5.23).
9. The total float equals 5, 5, 6, 5, and 8 for A, B, D, E, and F, respectively.
Some of this float is restricted; some is not. This subject is discussed
in the following section.
Figure 5.22 Network for example 5.1
Figure 5.23 Solution for example 5.1