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Appendix
The proof of Lemma 1 is presented in the following.
Proof (Lemma 1). We may start from Step 3 of the outline of the proof presented
after Lemma 1. Hence we have
(
A
,
b
,
c
)
|
= X ʸ,
(6)
[ F 1 /x 1 ] ... [ F m /x m ], and the first step is to construct a team X
for X :=
{∅}
such that
(
A
,
b
(
c
))
|
= X ʸ.
(7)
For this, we first define the operation auto. By item 4 of Theorem 8, for all
a
list-
ing a 1 ,...,a k− 1
A there exists an automorphism f a which maps
a
pointwise to
ʵ (
), but leaves all elements in rows of distance > 1fromrow( a 1 ) ,..., row( a k− 1 )
fixed. Let
a
) be the group generated by the automorphisms f a where f a
is obtained from item 4 of Theorem 8 and a is a sequence listing a 1 ,...,a k− 1 ∈ A
such that 2 < row( a i ) <n− 1, for 1 ≤ i ≤ k− 1. For a team Y of A ,wethenlet
F
=( F,
auto( Y ):=
{
f
s
|
f
∈F
,s
Y
}
.
Next we will define the operation swap. For this, we will first define mappings
mid and h .Weletmidmap m -sequences of
{
1 ,...,n
}
into
{
1 ,...,n
}
so that,
m ,
for any
p
:= ( p 1 ,...,p m )and
q
:= ( q 1 ,...,q m )in
{
1 ,...,n
}
1. 1 < mid(
p
) <n ,
2.
i
m : mid(
p
)
= p i ,
3.
l
m :if
p {
1 ,...,l
}
=
q {
1 ,...,l
}
,then
i
l : p i < mid(
p
)iff
q i < mid(
q
).
 
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