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ds
dr
rd
θ
r
r
d
θ
O
Figure A3.3.
and
1
2 r 0
A 2 A 1 =
(A3.11)
Substituting Eqs. (A3.10) and (A3.11) into Eq. (A3.9)gives
v 0 t
r 0
sin i 0 =
(A3.12)
Comparison with Eq. (A3.7) means that, in the limit when
t ,
0,
d t
d
p
=
(A3.13)
The ray parameter p is therefore the slope of the curve of travel time versus epicentral angle
(Fig. 4.16) and so, for any particular phase, is an observed function of the epicentral angle.
Let d s be the length of a short segment of a ray, as shown in Fig. A3.3. Then, using
Pythagoras' theorem on the infinitesimal triangle, we obtain
(d s ) 2
(d r ) 2
) 2
=
+
( r d
θ
(A3.14)
However, from Eq. (A3.7)wehave
r sin i
v
r
v r
d
d s
(A3.15)
p
=
=
Eliminating d s from Eqs. (A3.14) and (A3.15)gives an expression for d
θ
,
r 4 (d
) 2
p 2 v 2
θ
(d r ) 2
r 2 (d
) 2
=
+
θ
(A3.16)
which, upon rearranging, becomes
p d r
d
θ =
(A3.17)
p 2 ) 1 / 2
r ( r 2
/ v 2
Integrating this equation between the surface ( r = r 0 ) and the deepest point ( r = r min )gives an
expression for
:
= 2 p
r 0
d r
(A3.18)
p 2 ) 1 / 2
r ( r 2
/
v 2
r = r min
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