Geoscience Reference
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promotes metamorphic reactions and has a major impact on the thermodynamics
of re-equilibration.
Problems
1. Estimate Table 7.2 for 4000 and 4500 Ma. Discuss the implications of the rela-
tive heat-generation values in this table, particularly with respect to the Archaean
Earth.
2. Calculate the phase difference between the daily and annual surface temperature vari-
ations that would be measured at depths of 2 and 5 m in a sandstone.
3. Taking T 0 as 40 C for the annual variation in surface temperature, calculate the depth
at which the variation is 5 C. What is the phase difference (in weeks) between the
surface and this depth?
4. Calculate an equilibrium geotherm for 0 z d from the one-dimensional heat-flow
equation, given the following boundary conditions:
(i) T = 0at z = 0 and
(ii) T
d .
Assume that there is no internal heat generation.
5. Calculate an equilibrium geotherm from the one-dimensional heat-flow equation given
the following boundary conditions:
(i) T /∂ z = 30 Ckm 1 at z = 0km and
(ii) T = 700 Cat z = 35 km.
Assume that the internal heat generation is 1 Wm 3 and the thermal conductivity is
3Wm 1 C 1 .
6. On missions to Venus the surface temperature was measured to be 740 K, and at
three sites heat-producing elements were measured (in percentage of total volume)
as follows (ppm, parts per million).
=
T d at z
=
Venera 8
Venera 9
Venera 10
K (%)
0.47 ± 0.08
0.30 ± 0.16
4 ± 1.2
U (ppm)
0.60
±
0.16
0.46
±
0.26
2.2
±
0.2
Th (ppm)
3.65
±
0.42
0.70
±
0.34
6.5
±
2
The density of the Venusian crust can be taken, from a measurement by Venera
9, to be 2.8 × 10 3 kg m 3 . Calculate the heat generation in
Wm 3
at each site.
(From Nisbet and Fowler (1982).)
7. Using the one-dimensional equilibrium heat-conduction equation, calculate and plot
the Venus geotherms (Aphroditotherms) of Problem 6 down to 50 km depth at each
site. Assume that the conductivity is 2.5 W m 1 C 1 (a typical value for silicates) and
that, at a depth of 50 km, the heat flow from the mantle and deep lithosphere of Venus
is 21 × 10 3 Wm 2 . What have you assumed in making this calculation? What do
these Aphroditotherms suggest about the internal structure of the planet?
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