Geoscience Reference
In-Depth Information
Figure 5.9. A gravity
anomaly due to a sphere
of radius b buried at a
depth h . The density of
surrounding medium is ρ ;
the density of the sphere
is ρ 1 . The density contrast
is
1.0
ρ = ρ 1 -
ρ
.
0
-2
-1
0
1
2
x/h
x
θ
h
g z
r
ρ
b
ρ 1
ρ 1 and radius b is buried
Figure 5.9 shows one problem. A sphere of density
with its centre at depth h in a medium with density
ρ
. The density contrast of the
sphere with respect to the surrounding medium,
ρ
,isgivenby
(5.42)
From the calculations in Section 5.2 we know that the gravitational acceleration
g due to a sphere of mass m is Gm
ρ = ρ 1 ρ
r 2 .However, that is the acceleration at point
Pinthe radial direction r , and in this particular case we need to determine the
vertical component of gravity, g z :
g z
/
= g cos θ
Gm
r 2
=
cos θ
Gm
r 2
h
r
=
Gmh
=
(5.43)
( x 2
+ h 2 ) 3 / 2
The gravity anomaly
g z is therefore given by
4 G
ρ π
b 3 h
g z =
(5.44)
3( x 2
+ h 2 ) 3 / 2
In SI units, Eq. (5.44)is
ρ
b 3 h
g z = 2 . 79 × 10 10
(5.45)
( x 2
+ h 2 ) 3 / 2
The anomaly due to this buried sphere is therefore symmetrical about the centre
of the sphere and essentially confined to a width of about two to three times the
depth of the sphere (Fig. 5.9).
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