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In-Depth Information
Now let
V
⊥
=
W
D
+
u
where
qB
2
W
D
=
(
F
⊥
×
B
)/
(2.53)
This substitution is motivated by the result we already have that
W
D
=
(
B
2
when
F
×
)/
⊥
=
E
B
q
E
. Substituting (2.53) into (2.52) yields
F
B
2
M
∂
W
D
/∂
t
+
M
∂
u
/∂
t
=
⊥
×
B
/
×
B
+
q
u
×
B
+
F
⊥
The first term on the left vanishes, while the first term on the right-hand side
equals
−
F
and thus cancels the other
F
term. This leaves
⊥
⊥
M
∂
u
/∂
t
=
q
(
u
×
B
)
The solution to this, of course, is just the gyromotion at frequency
=
qB
/
M
The interpretation we make is that in a frame moving at
W
D
, the particle
motion is pure gyration. This yields the concept of a guiding center motion, since
W
D
gives the velocity of the center of gyromotion. Some examples of guiding
center drifts due to various forces are as follows. For an electric field,
F
=
q
E
and
qB
2
B
2
W
D
=
q
E
×
B
/
=
E
×
B
/
For the gravitational field,
F
=
M
g
and
qB
2
W
D
=
M
g
×
B
/
B
2
,
For the inertial force
F
=−
M
∂
W
D
/∂
t
and, letting
W
D
=
E
×
B
/
qB
2
M
t
E
B
2
B
qB
2
W
D
=
(
F
×
B
)/
=
−
1
/
∂/∂
×
B
/
×
M
qB
2
W
D
=−
/
(∂
E
/∂
t
×
B
)
×
B
M
qB
2
W
D
=
/
(∂
E
/∂
t
)
Notice that this expression can be related to a displacement current in the plasma,
since using
J
=
(
ne
W
Di
−
ne
W
De
)
and
M
m
yields
ne
M
eB
2
nM
B
2
J
=
/
∂
E
/∂
t
=
/
∂
E
/∂
t
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