Geoscience Reference
In-Depth Information
Express the fractional collection efficiency (η i ) in terms of d pi ( d p in ft):
=− − (
(
)
)
η
1
exp
kQ LG
Ψ
(
)
(
) (
) ()
2
11
η
=− −
1
exp(.)(.).
0 28513945
×
10
QQ d
i
LG p
(
)
5
=− −
1
exp
6 348
.
×
10
d
pi
Now calculate the collection efficiency for each particle size appearing in Table 18.1. For d p = 0.05
µm (1.64 × 10 -7 ft), for example:
(
)
(
)
(
)
5
=− −
5
7
=
η==− −
1
exp
6 348
.
×
10
d pi
1
exp
6 348
.
×
10
16410
.
×
0 0989
.
Table 18.2 shows the results (rounded) of the above calculations for each particle size. Now calculate
the overall collection efficiency:
η = ∑w i η i = (9.89 × 10 -4 ) + 0.0975 + 0.6325 + 12.980 + 16.00 + 12.00 + 8.00 + 50.00 = 99.71%
EXAMPLE 18.7
Problem: A vendor proposes to use a spray tower on a lime kiln operation to reduce the discharge
of solids to the atmosphere. The inlet loading is to be reduced in order to meet state regulations.
The vendor's design calls for a certain water pressure drop and gas pressure drop across the tower.
Determine whether this spray tower will meet state regulations. If the spray tower does not meet
state regulations, propose a set of operating conditions that will meet the regulations (USEPA,
1984b, p. 81).
Given:
Gas flow rate = 10,000 acfm
Water rate = 50 gal/min
Inlet loading = 5.0 grains/ft 3
Maximum gas pressure drop across the unit = 15 in. H 2 O
Maximum water pressure drop across the unit = 100 psi
Water pressure drop = 80 psi
Gas pressure drop across the tower = 5.0 in. H 2 O
State regulations require a maximum outlet loading of 0.05 grains/ft 3 . Assume that the contact
power theory applies (USEPA, 1984a, p. 9-15).
TABLE 18.2
Particle Size Data
d p (ft)
w i (%)
η i
w i η i (%)
1.64 × 10 -7
0.01
0.0989
9.89 × 10 -4
9.84 × 10 -7
0.21
0.4645
0.0975
2.62 × 10 -6
0.78
0.8109
0.6325
9.84 × 10 -6
13
0.9981
12.98
2.62 × 10 -5
16
1
16
4.27 × 10 -5
12
1
12
5.91 × 10 -5
8
1
8
6.56 × 10 -5
50
1
50
 
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