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Express the value of the dust collected in terms of pressure drop ∆ p . Recall that
η = ∆ p /(∆ p + 5.0)
Thus,
Value of dust collected = 0.143[∆ p /(∆ p + 5.0)]($/min)
Express the cost of power in terms of pressure drop ∆ p :
Brake horsepower ( Bhp ) = Q p /η′
where
Q = Volumetric flow rate.
p = Pressure drop (lb/ft 2 ).
η′ = Fan ef iciency.
= (
) × (
) ×
(
)
2
3
Cost of power
p
lbf/ft2
50,000 ft /min
1/44,200 kW-min/ft-lb
(
) ×
×
(
1/0.55)
×
0.06 $/kW
-h
(
1/60 hr/min
)
=
0 002
p
$/min
Set the cost of power equal to the value of dust collected and solve for ∆ p in lb/ft 2 . This represents
breakeven operation. Then, convert this pressure drop to in. H 2 O. To convert from lb/ft 2 to in. H 2 O,
divide by 5.2.
(0.143)∆ p /(∆ p + 5) = 0.002∆ p
Solving for ∆ p ,
p = 66.5 lb/ft 2 = 12.8 in. H 2 O
Calculate the collection efficiency using the value of ∆ p calculated above:
η = 66.5/(66.5 + 5) = 0.93 = 93.0%
EX AMPLE 17.16
Problem : Determine capital, operating, and maintenance costs on an annualized basis for a textile
dye and finishing plant (with two coal-fired stoker boilers) where a baghouse is employed for par-
ticulate control. Operating, design, and economics factors age given (USEPA, 1984b, p. 123).
Given:
Exhaust volumetric flow from two boilers = 70,000 acfm
Overall fan efficiency = 60%
Operating time = 6240 hr/yr
Surface area of each bag = 12.0 ft 2
Bag type = Teflon® ® felt
Air-to-cloth ratio = 5.81 acfm/ft 2
Total pressure drop across the system = 17.16 lb f /ft 2
Cost of each bag = $75.00
Installed capital costs = $2.536/acfm
Cost of electrical energy = $0.03/kWh
Yearly maintenance cost = $5000 plus yearly cost to replace 25% of the bags
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