Geoscience Reference
In-Depth Information
2
:
7
2
xx
yy
2
8
9
5
6
m
xy
2
At the centre of the Mohr circle, the mean normal stress gives
xx
yy
xx
yy
cos
2
m
yy
m
yy
2
2
The Mohr-Coulomb failure criterion states:
sin
. This provides
m
m
sin
cos
2
(
sin
cos
2
)
m
m
yy
yy
m
With
xy
sin
2
sin
sin
2
xy
m
m
one obtains
sin
sin
2
xy
1
sin
cos
2
yy
In similar manner one obtains
sin
sin
2
xy
1
sin
cos
2
xx
For the coaxial case without dilatancy (
= 0) it follows from (9.16) for the final
stage
cos
sin
xy
R
sin
1
sin
sin
yy
This complies with
. Obviously, the main stresses
rotate from the initial state towards final state (Fig 9.13).
= 45
=
, and thus
xx
yy
application 9.5
Find
cr of equation (9.14) and elaborate (9.15b).
Search WWH ::




Custom Search