Geoscience Reference
In-Depth Information
1. Finding numbers n 1 and n 2 from conditions P n 1
P 1
P n 1 +1 , P n 2
P n 2 +1
2. Then three cases are considered depending on the magnitude of differ-
ence n 2 n 1 : n 2 >n 1 +1
P 2
∆τ ( P 1 , P 2 ))
=
( P i ) (
0for i<n 1
or
i>n 2 +1;
∂α
( P 1 P i +1 ) 2
( P i P i +1 )
1
2
∆τ ( P 1 , P 2 ))
=
=
( P i ) (
, r i
n 1 ;
∂α
( P 1 P i ) 2
P 1 P i 1
2
P i −1 P i + 1
∆τ ( P 1 , P 2 ))
=
( P i ) (
2 ( P i P i +1 ),
∂α
=
for
i
n 2 + 1 ;
(5.27)
1
2 ( P i −1 P i +1 ), for n 1 +2
∆τ ( P 1 , P 2 ))
=
( P i ) (
i
n 2 −1;
∂α
( P i P 2 ) 2
P i P 2 1
2
P i P i +1 + 1
∆τ ( P 1 , P 2 ))
=
=
( P i ) (
2 ( P i −1 P i ), for i
n 2 ;
∂α
( P i −1 P 2 ) 2
P i −1 P i
1
2
∆τ ( P 1 , P 2 ))
=
=
( P i ) (
, r i
n 2 +1.
∂α
=
n 2
n 1 +1.Thiscasediffersfromthelatterbythederivativebeingequalto:
( P 1 P i ) 2
( P i P 2 ) 2
P i P i +1
P 1 P 2 1
2
P i −1 P i 1
∆τ ( P 1 , P 2 ))
=
( P i ) (
∂α
2
(5.28)
=
=
for
i
n 1 +1
n 2
=
n 2
n 1 :
∆τ ( P 1 , P 2 ))
=
( P i ) (
0for i<n 1
or
i>n 1 +1;
∂α
( P 1 P i +1 ) 2 −( P i P 2 ) 2
P i P i +1
P i P 2 + 1
2
∆τ ( P 1 , P 2 ))
=
( P i ) (
,
∂α
(5.29)
=
=
for
i
n 1
n 2 ,
( P i −1 P 2 ) 2 −( P 1 P i ) 2
P i −1 P i
P 1 P i + 1
2
∆τ ( P 1 , P 2 ))
=
( P i ) (
,
∂α
=
=
for
i
n 1 +1
n 2 +1.
Note that, the volume extinction coefficient in the described algorithm is
applied after recalculating per the pressure unit
α P ( P i ), while it has been
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