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B
Fq
ðÞ:
ð
6
:
39
Þ
Similarly, we have:
Fq f :
B f
ð
6
:
40
Þ
, and according to the Taylor series we
We expand B
Fq
ðÞᄐ
Fq f þ
q
q f
obtain:
Fq f þ
þ
d 2 B
dq 2
2
dB
dq
1
2
B
q
q f
q
q f
þ ...
ð
6
:
41
Þ
!
f
f
It follows from ( 6.3 ) that:
=
;
0
1
0
1
0
1
dB
dq
r
M
N cos B
M
@
A f
@
A f
@
A f
V f 2 cos B f
0
1
:
ð
6
:
42
Þ
d 2 B
dq 2
@
A f
ʷ f 2
cos B f sin B f 1
þ
4
Inserting ( 6.40 ) and ( 6.42 ) into ( 6.41 ) gives:
q
2
1
2 cos B f sin B f 1
V f 2 cos B f q
ʷ f 2
B
B f þ
q f
þ
4
q f
:
ð
6
:
43
Þ
According to the first equation in ( 6.38 ), we get:
9
=
y 4
t f sec B f
2N f
t sec B f
24N f
y 2
6t f þ ʷ
2
f
q
q f
þ
5
þ
:
ð
6
:
44
Þ
t f sec 2 B f
4N f
2
;
y 4
q
q f
Inserting again into ( 6.43 ) and rearranging yields:
y 4
t f
t f
24M f N f
2M f N f y 2
3t f þ ʷ
2
2
f t f
B
B f
þ
5
þ
f
9
ʷ
:
ð
6
:
45
Þ
Combining ( 6.45 ) with the second equation in ( 6.38 ), the formula for the inverse
solution of the Gauss projection can be obtained as follows:
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