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sin
ʻ 0
sin m
cos u 1 cos u 2
˃ 1 :
ð
5
:
107
Þ
sin
In addition, applying the cotangent theorem to the triangle P 0 1 P 0 2 N 0 , replacing
ʻ
with
ʻ 0 gives:
9
=
; :
cot A 1
tan u 2 cos u 1 csc
ʻ 0
sin u 1 cot
ʻ 0
ʻ 0
cos u 1 tan u 2 sin u 1 cos ʻ 0
sin
ð
5
:
108
Þ
tan A 1
In this way the estimated value A 1 of A 1 is obtained.
In the right triangle P 0 1 P 0 2 Q 1 , we have:
9
=
sin m cot A 1
sin u 1
cot M
:
ð
5
:
109
Þ
sin u 1
;
sin m tan A 1
tanM
Hence, the estimated value of M is obtained.
We calculate m according to ( 5.107 ) and compute ʱ 0 and ʲ 0 according to
( 5.100 ) and ( 5.92 ); the required accuracy is the same as for the direct solution.
Finally, we calculate the longitude difference on the spheroid using the
expression:
h
i
0
0 sin
ʻ ᄐ
l
þ
sin m
ʱ
˃ þ ʲ
˃
cos 2M
ð
þ ˃
Þ
:
ð
5
:
110
Þ
Solution of Spherical Triangles
1. Find
˃
As shown in Fig. 5.43 , applying the cosine law to the spherical triangle
P 0 1 P 0 2 N 0 gives:
cos
˃ ᄐ
sin u 1 sin u 2 þ
cos u 1 cos u 2 cos
ʻ:
ð
5
:
111
Þ
2. Find A 1 and A 2
As shown in Fig. 5.43 , applying the cotangent law to the spherical triangle
P 0 1 P 0 2 N 0 gives:
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