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sin
ʻ
0
sin m
ᄐ
cos u
1
cos u
2
˃
1
:
ð
5
:
107
Þ
sin
In addition, applying the cotangent theorem to the triangle P
0
1
P
0
2
N
0
, replacing
ʻ
with
ʻ
0
gives:
9
=
;
:
cot A
1
ᄐ
tan u
2
cos u
1
csc
ʻ
0
sin u
1
cot
ʻ
0
ʻ
0
cos u
1
tan u
2
sin u
1
cos ʻ
0
sin
ð
5
:
108
Þ
tan A
1
ᄐ
In this way the estimated value A
1
of A
1
is obtained.
In the right triangle P
0
1
P
0
2
Q
1
, we have:
9
=
sin m cot A
1
sin u
1
cot M
ᄐ
:
ð
5
:
109
Þ
sin u
1
;
sin m
tan A
1
tanM
ᄐ
Hence, the estimated value of M is obtained.
We calculate m according to (
5.107
) and compute ʱ
0
and ʲ
0
according to
(
5.100
) and (
5.92
); the required accuracy is the same as for the direct solution.
Finally, we calculate the longitude difference on the spheroid using the
expression:
h
i
0
0
sin
ʻ ᄐ
l
þ
sin m
ʱ
˃ þ ʲ
˃
cos 2M
ð
þ ˃
Þ
:
ð
5
:
110
Þ
Solution of Spherical Triangles
1. Find
˃
As shown in Fig.
5.43
, applying the cosine law to the spherical triangle
P
0
1
P
0
2
N
0
gives:
cos
˃ ᄐ
sin u
1
sin u
2
þ
cos u
1
cos u
2
cos
ʻ:
ð
5
:
111
Þ
2. Find A
1
and A
2
As shown in Fig.
5.43
, applying the cotangent law to the spherical triangle
P
0
1
P
0
2
N
0
gives:
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