Geoscience Reference
In-Depth Information
h
i
dx
2
3
2
dz
1
þ
P
R
A
ᄐ
:
d
2
z
dx
2
P
Since P is the coordinate origin, the z-axis and the x-axis are the normal and
tangent to the normal section, respectively; obviously:
9
=
x
P
ᄐ
z
P
ᄐ
0
0
1
dz
dx
:
ð5:29Þ
@
A
P
ᄐ
0
;
Hence, the radius can be expressed as:
1
d
2
z
R
A
ᄐ
dx
2
P
:
It is obvious that solving R
A
is made easier due to the establishment of the new
d
2
z
dx
2
coordinate system P-xyz. Here,
is the curvature of the normal section in an
P
arbitrary direction at point P. Taking the derivative with respect to x in (
5.28
)
repeatedly, and with (
5.29
), we obtain:
dx
2
d
2
z
2e
0
2
cos
2
B cos
2
A
2
2N
P
þ
ᄐ
0
:
Namely:
P
ᄐ
e
0
2
cos
2
B cos
2
A
N
d
2
z
dx
2
1
þ
:
Hence, the formula for the radius of curvature of the normal section in an
arbitrary direction is expressed as:
N
R
A
ᄐ
e
0
2
cos
2
B cos
2
A
:
ð5:30Þ
1
þ
This formula indicates that R
A
is not only dependent on the latitude B of a given
point but also on the azimuth A of the normal section. However, it is independent of
the longitude L of the point. The point P is assumed on the initial meridian while
deriving the formula. It is applicable everywhere in the world. Given the location of
the point, its latitude B will be known. At this point, both N and cosB are the specified
constants. In this case, R
A
varies only with the azimuth A of the normal section.
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