Geoscience Reference
In-Depth Information
h
i
dx 2
3
2
dz
1
þ
P
R A
:
d 2 z
dx 2
P
Since P is the coordinate origin, the z-axis and the x-axis are the normal and
tangent to the normal section, respectively; obviously:
9
=
x P
z P
0
0
1
dz
dx
:
ð5:29Þ
@
A P
0
;
Hence, the radius can be expressed as:
1
d 2 z
R A
dx 2 P :
It is obvious that solving R A is made easier due to the establishment of the new
d 2 z
dx 2
coordinate system P-xyz. Here,
is the curvature of the normal section in an
P
arbitrary direction at point P. Taking the derivative with respect to x in ( 5.28 )
repeatedly, and with ( 5.29 ), we obtain:
dx 2
d 2 z
2e 0 2 cos 2 B cos 2 A
2
2N
P þ
0
:
Namely:
P
e 0 2 cos 2 B cos 2 A
N
d 2 z
dx 2
1
þ
:
Hence, the formula for the radius of curvature of the normal section in an
arbitrary direction is expressed as:
N
R A
e 0 2 cos 2 B cos 2 A :
ð5:30Þ
1
þ
This formula indicates that R A is not only dependent on the latitude B of a given
point but also on the azimuth A of the normal section. However, it is independent of
the longitude L of the point. The point P is assumed on the initial meridian while
deriving the formula. It is applicable everywhere in the world. Given the location of
the point, its latitude B will be known. At this point, both N and cosB are the specified
constants. In this case, R A varies only with the azimuth A of the normal section.
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