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In-Depth Information
G
X
n
Gm
1
r
1
þ
Gm
2
r
2
þþ
Gm
n
r
n
¼
m
i
r
i
V
¼
ð
4
:
9
Þ
i¼1
The mass is continuously distributed within the body, and hence it only requires
conversion of the sum of (
4.9
) to an integral to obtain the formula for gravitational
potential of the body:
G
ð
dm
r
V
¼
,
ð
4
:
10
Þ
M
where dm denotes the differential mass element at the point (
ʾ
,
ʷ
,
ʶ
); it is a variable
q
x
2
2
2
of an integral (see Fig.
4.3
); r
is the distance
from dm to the attracted mass and the total mass of the integral area is M.
The centrifugal force or acceleration is given by:
¼
ð
ʾ
Þ
þ
ð
y
ʷ
Þ
þ
ð
z
ʶ
Þ
2
P
¼ ω
ˁ
,
ð
4
:
11
Þ
where
represents the vertical
distance from the point being studied to the axis of rotation (see Fig.
4.2
). Assume
that the spin axis coincides with the z-axis of the rectangular coordinate system;
then for the point (x, y, z):
ω
denotes the angular velocity of Earth rotation and
ˁ
p
x
2
ˁ ¼
þ
y
2
:
p
x
2
Inserting ˁ ¼
þ
y
2
into (
4.11
):
p
x
2
2
P
¼ ω
ð
þ
y
2
Þ
:
Obviously its potential function is:
2
:
¼
ω
x
2
y
2
Q
þ
ð
4
:
12
Þ
2
The force of gravity is the resultant of the gravitational force and the centrifugal
force, and thus the gravity potential W is equal to the sum of gravitational potential
V and the centrifugal potential Q, namely:
W
¼
V
þ
Q
:
ð
4
:
13
Þ
Hence the formula for gravity potential is expressed as:
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