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topological drawingsof G .The bisectionwidth of a graph G , denoted by b ( G ),isthe
smallest nonnegative integer such that there is a partition of the vertex set V = V 1
V 2
1
2
= b ( G ). The following result,
duetoPach and Tóth, relates the odd-crossing number of a graph to its bisection width. 1
3 |
V
|≤
V i
3 |
V
|
for i =1 , 2,and
|
E ( V 1 ,V 2 )
|
with
Theorem 4 ([10]). There is an absolute constant c 2 such thatif G is agraphwith n
vertices of vertex degrees d 1 ,...,d n ,then
odd-cr( G )+
n
b ( G )
c 2 log n
d i .
i =1
We also rely on the result duetoPach and Tóth [10] stated in the introduction.
Theorem 5 ([10]). Let G =( V,E ) be an n -vertex simple topological graph,such that
G does not contain t pairwise disjointedges. Then
c 3 n log 4 t− 8 n , where c 3
|
E ( G )
|≤
is an absolute constant.
From disjointedges to odd crossings. Using a combination of Theorems 3-5, we es-
tablish the following lemma.
Lemma 1. Let G =( V,E ) be simple topologicalbipartite graph on n vertices with
vertex degrees d 1 ,...,d n ,such that G does not containaset of t edges all disjointfrom
another set of t edges. Then
n
1
2 t log 8 t− 3 n + c 4 log n
c 4 n 1
d i ,
b ( G )
(1)
i =1
where c 4 is an absolute constant.
Proof: Since G does not contain 2 t pairwise disjoint edges, Theorem 5 yields
c 3 n log 8 t− 8 n.
|
E ( G )
|≤
(2)
Let V a and V b be the vertex classes of the bipartite graph G . Consider a simple
curve ʳ that decomposes the plane into two parts, containing all points in V a and V b ,
respectively. By applying asuitable homeomorphism to the plane that maps ʳ to a
horizontal line, G is deformed into a topological graph G such that (refer to Fig.1)
1. The vertices in V a are above the line y =1, the vertices in V b are below the line
y =0,
1 Pach and Tóth [10] defined the odd-crossing number of a graph G to be the minimumnumber
of pairs of edges that cross an odd number of times (over all drawingsof G ), including pairs of
edges with a common endpoint. However, since the number of pairs of edges with a common
endpoint is at most i =1 d i , this effects Theorem 4 only by a constant factor.
 
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