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drawing of G inherited from the drawing of G .Then
E
[pcr + ( G )]
E
[ x ]=
p 4
·
pcr + ( G ). 3 It follows from Theorem 6 that pcr + ( G )
pcr( G )
4 m
18 n
(note that this it true for any n
0), and this holds also for the expected
values:
E
[pcr + ( G )]
4
E
[ m ]
18
E
[ n ]. Plugging in the expected values we get
2 6
3 7 m 3
m 3
1
34 . 2
that pcr + ( G )
n 2 .
n 2
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3 Here we need the restriction that there are no adjacent crossings: an adjacent crossing
would survive with probability p 3 instead of p 4 . This was overlooked in a preliminary
version of this paper when this theorem was stated for pcr instead of pcr + .
 
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