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u 2
u 0
u 1
v 0
v 1
v 2
v 3
u 3
Fig. 3. A graph whose Fruchterman-
Reingold coordinates cannot be com-
puted by a radical computation tree.
Fig. 4. A graph whose Kamada-Kawai
coordinates cannot be computed by a
radical computation tree.
Let a> 0 be the distance from v 0 to v 1 (equal by symmetry to the distance from v 2
to v 3 )andlet b> 0 be the distance from v 1 to v 2 . We can then express the sumofall
the forces at vertex v 0 by the equation
2 a + b = 2 a 5 +3 a 4 b + a 3 b 2
5 a 2
b 2
1
a
1
a + b
1
5 ab
F 0 = a 2
,
2 a 3 +3 a 2 b + ab 2
and the sum of all the forces at vertex v 1 by the equation
a + b =
a 4 b
a 3 b 2 + a 2 b 3
a 2 + ab 4
ab + b 2
a 2 + 1
1
b
1
a + b 2
F 1 =
.
a 2 b + ab 2
In an equilibrium state we have F 1 = F 2 =0.Equivalently, the numerator p of F 1 and
the numerator q of F 2 are both zero, where
p ( a, b )=2 a 5 +3 a 4 b + a 3 b 2
5 a 2
b 2 =0
5 ab
a 4 b
a 3 b 2 + a 2 b 3
a 2 + ab 4
ab + b 2 =0 .
q ( a, b )=
To solve this system of two equations and two unknowns we can eliminate variable a
and produce the following polynomial, shown as a product of irreducible polynomials,
whose roots give the values of b that lead to a solution.
1
3 b 2 (3 b 15
48 b 12 + 336 b 9
1196 b 6 + 1440 b 3 + 144) .
The factor b 2 corresponds to degenerate drawings and may safely be eliminated. Let f
be the degree-fifteen factor; then f ( x )= g ( x 3 ) for a quintic polynomial g . A radical
computation tree can compute the roots of f from the roots of g , so we need only show
that the roots of g cannot be computed in a radical computation tree. To do this, we
convert g to a monic polynomial h with the same splitting field, via the transformation
h ( x )= x 5
144 g (6 /x )= x 5 +60 x 4
299 x 3 + 504 x 2
432 x + 162 .
The polynomial h canbeshowntobeirreducible by manually verifying that it has no
linear or quadratic factors. Its discriminant is
2 6
3 9
2341 2
2749,and h factors
modulo primes 5 and 7 (which do not divide the discriminant) into irreducibles:
·
·
·
( x +1)( x 4 +3 x 3 +6 x 2 + x +1) (mod7)
h ( x )
( x 2 +3 x +4)( x 3 +2 x 2 + x +3) (mod5) .
h ( x )
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