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iff there exist k
[ d ] such that
|
x k
y k |
|
x i
y i |
< 1 for all i
[ d ]
\{
k
}
=1and
.It
remains to show that two cubes ˆ ( v x ) and ˆ ( v y ) have proper contact iff ( v x ,v y )
E S n :
Suppose ( v x ,v y )
E S . Then, it holds
x
y
1 =1;thatis
! k
[ d ] with
|
x k
y k |
=1
|
x i
y i |
=0for all i
[ d ]
\{
k
}
.Wlog let x
dom y . Consider the characteristic
and
y of the cubes ˆ ( v x ) and ˆ ( v y ).Let e k denote the k th standard basis
corners A
·
x and A
·
d , then for the characteristic corners hold: ( A
vector of
e k .
This implies that the two cubes ˆ ( v x ) and ˆ ( v y ) have proper contact which is of size
cs ( ˆ ( v x ) , ˆ ( v y )) = 1
R
·
x
A
·
y )= A
·
( x
y )= A
·
ʵ .
Suppose ( v x ,v y ) /
E S ,then
x
y
1
2. Either there is a coordinate k
[ d ],
such that
|
x k
y k |≥
2 or there exist at least two coordinates k,j
[ d ] such that
|
x k
y k |≥
1. It is easy to check, that in either case, there is a coordinate in ( A
·
x
A
·
y )
1+ ʵ , and hence, the cubes ˆ ( v x ) and ˆ ( v y ) are
which has an absolute valueof
E S the space is sp( ˆ ( v x ) , ˆ ( v y ) ,e k )
disjoint. Thusfor( v x ,v y ) /
ʵ for k =1 ,...,d .
We proceed with the translation vectors and moving sets: For e =( v x ,v y )
E S ,
there exists a unique k
[ d ] with
|
x k
y k |
=1and x i = y i for i
= k .Wlog we
assume x
dom y . Then, the direction vector is defined as d ( e ):= e k and the moving
set as M ( e ):=
[ n ] d ,z k >x k ,z i = x i for all i
.
Observe that the translation vector d ( e ) of edge e is parallel to each of the following
crucial ( d
{
v z |
z
= k
}
1)-dimensional facets: These are facets realizing the contacts corresponding
to edges of type ( u,v )
E
\{
e
}
with u
M ( e ) and v/
M ( e ). Additionally, it holds
sp ˆ ( u ) , ˆ ( v ) ,d i for w
that r i ( w ) ʴ
.
Following the same lines as the proof of Theorem 2, this shows that the construction
yields a UPCR with d -cubes for each subgraph of
nʴ < ʵ
∈{
u,v
}
/
E S and i
∈{
1 ,...,d
}
n .
S
5.2
Triangular Grid
Alam et al. [2] asked whether subgraphs of the triangular grid have UCuPCRs. In this
section, we answer this question affirmatively.
We introduce an unconventional definition of the triangular grid
T m,n =( V T ,E T )
of size m
×
n .For i
[ m ],and j
[ n ],thevertexsetis V :=
{
b i,j }∪{
t i,j }
.Thesetof
edges is E := i =1 E i ,where E 1 := ( x i,j ,x i,j +1 ) with x
, E 2 := ( b i,j ,t i,j ),
E 3 := ( b i,j ,t i,j− 1 ), E 4 := ( b i,j ,t i− 1 ,j− 1 ),and E 5 := ( b i,j ,t i− 1 ,j ), see also Figure 5.
For fixed j , we call the vertex set of type
∈{
b,t
}
x i,j } i∈ [ m ] a line and two neighboring lines a
level .Edges between two lines are called level edges . Note that we have 2 n lines.
{
t 2 , 0
b 2 , 0
t 1 , 0
b 1 , 0
t 0 , 0
...
b 0 , 0 b 1 , 0
b 4 , 0
(a) (b) (c)
Fig. 5. (a) Triangular grid T 4 , 2 ; for thick edges, the moving sets are indicated by framed vertices
(b) UCuPCR ˆ of T 4 , 2 (c) Illustration of modification step.
 
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