Environmental Engineering Reference
In-Depth Information
-2Gxz - 2Gyz
x(x - 2) - k[y -
(
)
M
=
λ
.
.
(5.28)
1
2
α
(
1
+
y -
)
β
(
1
+
y
)
+
2
αβ
]
5.4
VibrationAnalysis
The.longitudinal.motion.of.a.stable.helicopter.will.be.found.to.exhibit.two.
modes,.which.are.damped.oscillations..The.irst.mode.with.light.damping.
and. a. relatively. long. period. is. called. the.
long-period
. or.
phugoid
. mode.. The.
second.heavy.damped.mode.is.referred.to.simply.as.the.
short-period
.mode..
The.equation.for.forced.vibration.without.damping.is:
2
∂
∂
=
(
)
m
x
+
Q
x
L - D - W
sin
θ
sin
Ω
.
t
.
(5.29)
11
2
Here:
Ω.is.a.forcing.frequency.acting.from.turbulence.movement;
t.is.a.time.of.a.wave.propagation;
m. is. the. mass. of. the. blade,. is. constant. all. the. time. and. doesn't. depend.
upon.movement.and.attitude.
We.assume.a.periodic.force.of.magnitude;.F.=.(L.-.D.-.W.sin.θ).sinΩt.
Here:
L.is.a.lift.force;
D.is.a.drag.wind.force;
W.is.a.weight.of.a.rotor.blade.
The.force.of.the.lift.is.actually.much.stronger.than.the.wind's.force.against.
the.front.side.of.the.blade,.which.is.called.
drag
..In.the.case.of.free.vibration.
when.turbulence.movement.doesn't.exist:.(L-D-W.sin.θ).sinΩt.=.0,.which.has.
the.following.solution.as:
8
.
x.=.C
1
sinϖt.+.C
2
cosϖt.
(5.30)
and.where.circular.frequency.ϖ.=.(Q
11
/m)
1/2
.
Here,.Q
11
.is.the.stiffness.of.the.rotor.blade.and.can.be.determined.using.
previous.equations..C
1
.and.C
2
.are.arbitrary.constants.
We.assume.C
1
.=.A.cosϕ;.C
2
.=.A.sinϕ..Here,.A.is.an.amplitude.of.vibration.
and.ϕ.is.a.phase.angle.of.vibration..We.input.this.into.Equation.(5.30).and.the
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