Civil Engineering Reference
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W
B
D
W
C
2 m
E
4 m
A
2 m
2 m
F IGURE 18.16
Portal frame of
Ex. 18.8
(a)
(b)
4 u
4 u
4 u
3 u
u
u
u
u
B
D
B
D
B
D
2 u
2 u
2 u
2 u
C
C
2 u
2 u
u
u
E
E
E
A
A
A
(c)
(a)
(b)
F IGURE 18.17 Collapse mechanisms for the frame of Ex. 18.8
the beam and sway mechanisms. However, in this case, the moments at B due to the
vertical load at C and the horizontal load at B oppose each other so that the moment
at B will be the smallest of the five peak moments and plastic hinges will form at the
other locations. We say, therefore, that there is a hinge cancellation at B; the angle
ABC then remains a right angle. We shall now examine each mechanism in turn to
determine the value of W required to cause collapse. We shall designate the plastic
moment of the frame as M P .
BEAMMECHANISM
Suppose that BC is given a small rotation θ . Since CD
CB then CD also rotates
through the angle θ and the relative angle between CD and the extension of BC is 2 θ .
Then, from the principle of virtual work
=
W 2 θ
=
M P θ
+
M P 2 θ
+
M P θ
(i)
which gives
W
=
2 M P
 
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