Civil Engineering Reference
In-Depth Information
w
u
A
f
B
B
A
C
L
u
+ f
R A
R B
F IGURE 18.14
Collapse
mechanism for a
propped cantilever
x
L
x
(a)
(b)
The total load on AC is wx and its centroid (at x /2 from A) will be displaced a vertical
distance
δ
/2. The total load on CB is w ( L
x ) and its centroid will suffer the same
vertical displacement
δ
/2. Then, from the principle of virtual work
wx 2 +
x ) 2 =
w ( L
M P θ +
M P ( θ + φ )
Note that the beam at B is free to rotate so that there is no plastic hinge at B.
Substituting for
δ
from Eq. (i) and φ from Eq. (ii) we obtain
M P θ
wL θ x
x
2 =
M P θ
+
+
θ
L
x
or
M P θ 2
wL θ x
x
2 =
+
L
x
Rearranging
2 L
2 M P
Lx
x
w
=
(iii)
L
x
For a minimum value of w ,(d w /d x )
=
0. Then
d w
d x =
2 M P
L
x ( L
x )
(2 L
x )( L
2 x )
=
0
x 2 ( L
x ) 2
which reduces to
x 2
2 L 2
4 Lx
+
=
0
Solving gives
x
=
0 . 586 L (the positive root is ignored)
Then substituting for x in Eq. (iii)
11 . 66 M P
L 2
w (at collapse)
=
 
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