Civil Engineering Reference
In-Depth Information
Ans. M
AB
=
M
CB
=
0
M
BA
=
30 kN m
M
BC
=−
36 kN m,
M
BD
=
6kNm
M
DB
=
3kNm.
P.16.26
The frame shown in Fig. P.16.26 is pinned to the foundation of A and
D and has members whose flexural rigidity is
EI
. Use the moment distribution
method to calculate the moments in the members and draw the bending moment
diagram.
50 kN
B
C
3 m
25 kN
3 m
A
D
2 m
4 m
F
IGURE
P.16.26
Ans. M
A
=
M
D
=
0
M
B
=
11
.
9kNm
M
C
=
63.2 kNm.
P.16.27
Use the moment distribution method to calculate the bending moments
at the joints in the frame shown in Fig. P.16.27 and draw the bending moment
diagram.
C
10 kN
B
3
EI
4 m
2
EI
5 m
2
EI
D
A
5 m
3 m
F
IGURE
P.16.27
Ans. M
AB
=
M
DC
=
0
M
BA
=
12.7 kNm
=−
M
BC
M
CB
=−
13
.
9kNm
=−
M
CD
.
P.16.28
The frame shown in Fig. P.16.28 has rigid joints at B, C and D and is pinned to
its foundation at A and G. The joint D is prevented from moving horizontally by the
member DF which is pinned to a support at F. The flexural rigidity of the members
AB and BC is 2
EI
while that of all other members is
EI
.
