Civil Engineering Reference
In-Depth Information
A
F
B
E
1.5 m
C
D
5kN
5kN
5kN
5kN
2.5 m
2.5 m
2.5 m
2.5 m
2.5 m
F
IGURE
P.5.1
P.5.2
Calculate the sag at the point B in the cable shown in Fig. P.5.2 and the tension
in each of its segments.
Ans
.0
.
81m relative to A.
T
AB
=
4
.
9 kN,
T
BC
=
4
.
6 kN,
T
DC
=
4
.
7 kN.
A
0.7 m
D
B
C
0.5 m
1kN
2kN
2m
2m
2m
F
IGURE
P.5.2
P.5.3
Calculate the sag, relative to A, of the points C and D in the cable shown in
Fig. P.5.3. Determine also the tension in each of its segments.
Ans
.C
=
=
3
.
1m,
T
AB
=
10
.
98 kN,
T
BC
=
9
.
68 kN,
T
CD
=
4
.
2m,D
9
.
43 kN.
A
0.5 m
E
2.6 m
B
D
C
3kN
4kN
5kN
4m
5m
5m
4m
F
IGURE
P.5.3
P.5.4
A cable that carries a uniform horizontally distributed load of 10 kN/m is sus-
pended between two points that are at the same level and 80m apart. Determine the
minimum sag that may be allowed at mid-span if the maximum tension in the cable is
limited to 1000 kN.
Ans
.8
.
73m.
P.5.5
Asuspension cable is suspended fromtwopoints 102mapart and at the same hor-
izontal level. The self-weight of the cable can be considered to be equivalent to 36N/m
of horizontal length. If the cable carries two concentrated loads each of 10 kN at 34m
and 68m horizontally from the left-hand support and the maximum sag in the cable
is 3m, determine the maximum tension in the cable and the vertical distance between
the concentrated loads and the supports.
Ans
. 129
.
5 kN, 2
.
96m.
