Agriculture Reference
In-Depth Information
9.3.3.1 Resultant Horizontal Hydraulic Conductivity
Consider a soil column having n layers, and the depth (m) and horizontal hydraulic
conductivity (m/d) of the layers are d 1 , d 2 , d 3 ,
K n ,
respectively (Fig. 9.9 ) . Assume that the hydraulic gradient in the horizontal direction
is grad
...
d n and K 1 , K 2 , K 3 ,
...
ϕ
.
Fig. 9.9 Schematic of
horizontal hydraulic
conductivity
1
q 1
d 1
K 1
2
q 2
d 2
K 2
3
q 3
d 3
K 3
n
q n
d n
K n
The total depth of the layers, D
=
d 1 + d 2 + d 3 +
...
d n
Flow through unit width of layer d 1 under grad
ϕ
hydraulic gradient, q 1 =
A 1 V 1
=
(1
×
d 1 )
×
( K 1 grad
ϕ
)
=
K 1 d 1 grad
ϕ
Similarly,
Flow through “ d 2 ”, q 2 =
ϕ
K 2 d 2 grad
Flow through “ d 3 ”, q 3 =
ϕ
K 3 d 3 grad
Flow through “ d n ”, q n =
ϕ
K n d n grad
Total flow through the layers,
i = 1
n
Q
=
q i =
( K 1 d 1 +
K 2 d 2 +
K 3 d 3 +···+
K n d n )grad
ϕ
or,
K i d i grad
Q
=
ϕ
(9.6)
Now, we assume that the equivalent horizontal hydraulic conductivity of the whole
column (layers) is K H (m/d). Then,
d i ×
Q = D
×
K H grad
ϕ =
K H grad
ϕ
(9.7)
where D is the depth of soil column.
Equating the Eqs. ( 9.6 ) and ( 9.7 ) , we get
 
 
 
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