Biomedical Engineering Reference
In-Depth Information
z (x)
=
1.4
x
2
1
1
2
−
−
0.5
−
FIGURE 6.16:
Transformation for Problem 19.
8
2
α/π
,
0
<α<π/
2
(b)
f
x
(
α
)
=
0
,
otherwise
.
25. Given that
x
has the CDF
⎧
⎨
0
,
α <
0
F
x
(
α
)
=
α,
0
≤
α<
1
⎩
1
,
1
≤
α.
2 ln(
x
) using the PDF technique.
26. Random variable
x
has the PDF
Find the PDF of
z
=−
2
α/
9
,
0
<α<
3
f
x
(
α
)
=
0
,
otherwise
.
1)
2
and event
A
Random variable
z
=
(
x
−
={
x
:
x
≥
1
/
2
}
. Find the PDF of random
variable
z
, given event
A
.
27. Random variable
x
is uniform between
−
1 and 1. Random variable
x
2
,
x
<
0
z
=
x
,
x
≥
0
.
Using the PDF technique, find
f
z
.
28. A voltage
v
is a Gaussian random variable with
η
=
0 and
σ
=
2. Random variable
v
v
=
v
2
/
R
represents the power dissipated in a resistor of
R
with
v
volts across the
w
resistor. Find (a)
f
w
, (b)
f
w
|
A
if
A
={
≥
0
}
.
v
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