Civil Engineering Reference
In-Depth Information
or, after integrating,
+
8400
4800
0000
0000
0000
0840
0480
0000
k
(2)
hS
hta
4(3)
htb
4(3)
=
and, since
a
=
b
,
=
0
.
0579
0
.
0290
8400
41640
0480
0000
0
0
k
(2)
hS
50(0
.
5)
2
4(3)(12)
2
.
.
.
0
0290
0
1157
0
0290
0
Btu/(hr-
◦
F)
=
0
0
.
0290
0
.
0579
0
0
0
0
0
Likewise, the element edge convection force vector is obtained by integration along the
two edges as
#
%
&
(
1
−
r
1
0
1
1
f
(2)
hS
hT
a
t
2
+
r
0
0
−
s
1
=
a
d
r
+
b
d
s
1
+
s
0
−
1
−
1
5
.
9028
11
2
4
2
0
50(68)(0
.
5)
2
2(12)
2
.
8056
=
=
Btu/hr
5
.
9028
0
Identical procedures applied to the appropriate edges of elements 3 and 4 result in
=
0000
0840
04164
0048
0
0
0
0
k
(3)
hS
50(0
.
5)
2
4(3)(12)
2
.
.
00
0579
0
0290
0
Btu/(hr-
◦
F)
=
00
.
0290
0
.
1157
0
.
0290
0
0
0
.
0290
0
.
0579
=
0000
0000
0084
0048
00
0
0
k
(4)
hS
50(0
.
5)
2
4(3)(12)
2
00
0
0
Btu/(hr-
◦
F)
=
000
.
0579
0
.
0290
000
.
0290
0
.
0579
0
f
(3)
hS
.
5
9028
=
Btu/hr
11
.
8056
5
.
9028
0
0
f
(4)
hS
=
Btu/hr
5
.
9028
5
.
9028
