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associated with nodes on S 3 . To generalize, we rewrite Equation 7.41 as
f ( e g =− k ( e hS {
}+ f ( e )
hS
T
(7.42)
where
k ( e hS =
h [ N ] T [ N ] t d S
(7.43)
S
is the contribution to the element conductance matrix owing to convection on
portion S of the element boundary and
f ( e )
hS =
hT a {
N
}
t d S
(7.44)
S
is the forcing function associated with convection on S .
Incorporating Equation 7.42 into Equation 7.36, we have
k ( e ) {
}= f ( e Q + f ( e h + f ( e g + f ( e )
hS
T
(7.45)
where the element conductance matrix is now given by
k x
t d A
T
k y
T
k ( e ) =
N
N
N
N
+
x
x
y
y
A
2 h
h
[ N ] T
[ N ] T
+
[ N ] d A
+
[ N ] t d S
(7.46)
A
S
which now explicitly includes edge convection on portion(s) S of the element
boundary subjected to convection.
EXAMPLE 7.4
Determine the conductance matrix (excluding edge convection) for a four-node, rectan-
gular element having 0.5 in. thickness and equal sides of 1 in. The material has thermal
properties k x
4
3
= 20 Btu/(hr-ft- F ) and h = 50 Btu/(hr-ft 2 - F ).
= k y
s
r
Solution
The element with node numbers is as shown in Figure 7.9 and the interpolation functions,
Equation 6.56, are
1
2
Figure 7.9 Element
node numbering
for Example 7.4;
the length of each
edge is 1 in.
1
4 (1 r )(1 s )
N 1 ( r , s ) =
1
4 (1 + r )(1 s )
N 2 ( r , s ) =
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