Graphics Reference
In-Depth Information
u 3 v
R
v
w
T
u
P
S
Fig. 10.34. The vectors used to determine a plane equation from three points R, S
and T.
We begin with
i
j
k
u
×
v =
x u
y u
z u
x v
y v
z v
As w is perpendicular to u × v
x w
y w
z w
w ·
( u × v )=
x u
y u
z u
=0
x v
y v
z v
Expanding the determinant we obtain
x w
+ y w
+ z w
y u
z u
z u
x u
x u
y u
=0
y v
z v
z v
x v
x v
y v
which becomes
x R )
y R )
y S
y R
z S
z R
z S
z R
x S
x R
( x
+( y
+( z
z R )
y T
y R
z T
z R
z T
z R
x T
x R
x S
x R
y S
y R
×
=0
x T
x R
y T
y R
This can be arranged in the form ax + by + cz + d =0
where
a =
b =
y S
y R
z S
z R
z S
z R
x S
x R
y T
y R
z T
z R
z T
z R
x T
x R
c =
x S
x R
y S
y R
d =
( ax R + by R + cz R )
x T − x R
y T − y R
or
1
y R
z R
x R
1
z R
x R
y R
1
a =
1
y S
z S
b =
x S
1
z S
c =
x S
y S
1
1
y T
z T
x T
1
z T
x T
y T
1
d =
( ax R + by R + cz R )
Search WWH ::




Custom Search