Graphics Reference
In-Depth Information
()
=
[
]
H A
00
11
01
,,
if d
<
a or b
<
c
,
=
[]
,,
if a
===
b
c
d
,
=
[]
,,
otherwise
.
Note that in the special case h(
x
) = (f(
x
) = 0), where we are simply testing for zeros
of f, then
()
=
[]
Œ
[
]
[
]
π
[
]
HA
01
,,
if and only if
0
ab but ab
,
,
0 0
, .
We can also define Boolean operators between relational expressions. For
example, if
n
Æ
{}
rr
,:
R
01
,
12
are relational expressions with inclusion functions R
1
and R
2
, respectively, then an
inclusion function B for the logical
and
operator
n
Æ
{}
()
=
()
()
b
:
R
01
,
,
b
x
r
x and
r
x
,
1
2
is
()
=
[
]
(
()
=
[
]
)
(
(
)
=
[
]
)
BA
00
,,
if R A
00
,
or
and
R A
00
, ,
1
2
=
[]
(
()
=
[]
)
(
(
)
=
[]
)
11
,,
if R
A
11
,
R
A
11
, ,
1
2
=
[]
01
,,
otherwise
,
for all A Œ I(
R
n
).
If one is going to use interval analysis, then all relevant theorems and their proofs
need to be reformulated in that context. As an example of this, we consider one impor-
tant theorem from calculus.
18.3.1 Theorem.
(The Mean Value Theorem in Interval Analysis) Let f :
R
m
Æ
R
n
be a differentiable function. Let H
ij
be an inclusion function for ∂f
i
/∂x
j
and H the
inclusion function for the Jacobian matrix defined by
=
(
.
HH
ij
Then there exists an inclusion function F for f satisfying
()
=
(
[
]
)
+
()
-
(
)
FA
F
xx
,
HA A
x
,
for all A Œ I(
R
m
) and
x
Œ A.
Proof.
The theorem follows from basic facts about the Taylor expansion for f and
its error bounds.