Graphics Reference
In-Depth Information
() = [
]
H A
00
11
01
,,
if d
<
a or b
<
c
,
= []
,,
if a
===
b
c
d
,
= []
,,
otherwise
.
Note that in the special case h( x ) = (f( x ) = 0), where we are simply testing for zeros
of f, then
() = []
Π[
]
[
] π [
]
HA
01
,,
if and only if
0
ab but ab
,
,
0 0
, .
We can also define Boolean operators between relational expressions. For
example, if
n
Æ {}
rr
,:
R
01
,
12
are relational expressions with inclusion functions R 1 and R 2 , respectively, then an
inclusion function B for the logical and operator
n
Æ {}
() =
()
()
b
:
R
01
,
,
b
x
r
x and
r
x
,
1
2
is
() = [
]
(
() = [
]
)
(
(
) = [
]
)
BA
00
,,
if R A
00
,
or
and
R A
00
, ,
1
2
= []
(
() = []
)
(
(
) = []
)
11
,,
if R
A
11
,
R
A
11
, ,
1
2
= []
01
,,
otherwise
,
for all A ΠI( R n ).
If one is going to use interval analysis, then all relevant theorems and their proofs
need to be reformulated in that context. As an example of this, we consider one impor-
tant theorem from calculus.
18.3.1 Theorem. (The Mean Value Theorem in Interval Analysis) Let f : R m Æ R n
be a differentiable function. Let H ij be an inclusion function for ∂f i /∂x j and H the
inclusion function for the Jacobian matrix defined by
= ( .
HH ij
Then there exists an inclusion function F for f satisfying
() =
(
[
]
) +
() -
(
)
FA
F
xx
,
HA A
x
,
for all A ΠI( R m ) and x ΠA.
Proof. The theorem follows from basic facts about the Taylor expansion for f and
its error bounds.
Search WWH ::




Custom Search