Graphics Reference
In-Depth Information
Figure 6.18.
Computing the area of a polygon.
n
pp
pp
()
Ê
Ë
ˆ
¯
Â
12
2
01
i
-
A
=
det
.
(6.30)
0
i
i
=
Proof.
Consider Figure 6.18 and use Formula 6.7.3. The argument also works for
nonconvex polygons.
6.7.5
Formula.
The signed volume V of a tetrahedron with vertices
p
1
,
p
2
,
p
3
, and
p
4
is given by
ppp
ppp
ppp
ppp
1
1
1
1
Ê
ˆ
11
12
13
pp
pp
pp
-
-
-
Ê
ˆ
1
2
Á
Á
Á
˜
˜
˜
21
22
23
Á
Á
˜
˜
=
()
=
()
V
16
det
16
det
,
(6.31)
1
3
31
32
33
Ë
¯
1
4
Ë
¯
41
42
43
where
p
i
= (p
i1
,p
i2
,p
i3
). The value for V will be positive if we order the points so that
the ordered basis (
p
1
-
p
2
,
p
1
-
p
3
,
p
1
-
p
4
) induces the standard orientation of
R
3
.
Proof.
The first equality follows from Formula 6.7.2 and the fact that the paral-
lelolopiped defined by
p
1
-
p
2
,
p
1
-
p
3
, and
p
1
-
p
4
can be decomposed into six tetra-
hedra of equal volumes. The second equality in formula (6.31) follows from basic
properties of the determinant, in particular, the fact that the determinant of a matrix
is unchanged if a row of the matrix is subtracted from another row.
Let g: [a,b] Æ
R
2
be a differentiable curve in the plane. Let
p
Œ
R
2
. The set
Definition.
[
]
()
tab
p
g
t
Œ
[
]
,
is called the
region subtended by the curve
g
from the point
p
. See Figure 6.19(a).
6.7.6 Formula.
Let g: [a,b] Æ
R
2
, g(t) = (g
1
(t),g
2
(t)), be a curve in the plane. The
signed area A of the region subtended by the curve g from the origin is given by